Solution:
1. Move all terms to one side
25{x}^{2}+40x+16-28=0 2. Simplify 25{x}^{2}+40x+16-28 to 25x2+40x−12
25{x}^{2}+40x-12=0 3. Apply the Quadratic Formulax=\frac{-40+20\sqrt{7}}{50},\frac{-40-20\sqrt{7}}{50}

 4. Simplify solutions
x=-\frac{2(2-\sqrt{7})}{5},-\frac{2(2+\sqrt{7})}{5} Done!

8 0

3 years ago

a leatherback turtle swims at a constant rate of 2.5 kilometers per hour, at its constant rate of speed how long will it take fo

LekaFEV [45]

Hello there!

So, if this turtle is only going 2.5 miles per hour. This would mean that (EACH) hour, this turtle only arrived 2.5 miles. So, we do,

$\boxed{10.0 \left \{ {{2.5+2.5=5.0} \atop {2.5+2.5=5.0}} \right.}$

We would have to count how many ("2.5's" they are above.)

We count only 4.

I would take this turtle 4 miles to swim 10 kilometers.

5 0

4 years ago