Answer:
The probability that a jar contains more than 466 g is 0.119.
Step-by-step explanation:
We are given that a jar of peanut butter contains a mean of 454 g with a standard deviation of 10.2 g.
Let X = <u><em>Amount of peanut butter in a jar</em></u>
The z-score probability distribution for the normal distribution is given by;
Z = ~ N(0,1)
where, = population mean = 454 g
= standard deviation = 10.2 g
So, X ~ Normal()
Now, the probability that a jar contains more than 466 g is given by = P(X > 466 g)
P(X > 466 g) = P( > ) = P(Z > 1.18) = 1 - P(Z 1.18)
= 1 - 0.881 = <u>0.119</u>
The above probability is calculated by looking at the value of x = 1.18 in the z table which has an area of 0.881.
Answer:
Step-by-step explanation:
solution is (4,3)
OR
x=4
y=3
this point lies in both the tables.
we have to find a pair which lies on both.
Answer:
- x = 7
- x = 11
- 5
Step-by-step explanation:
◇◇•◇◇
♤♤•♤♤
- Given - <u>A </u><u>trapezium</u><u> </u><u>ABCD </u><u>with </u><u>non </u><u>parallel </u><u>sides </u><u>of </u><u>measure </u><u>1</u><u>5</u><u> </u><u>cm </u><u>each </u><u>!</u><u> </u><u>along </u><u>,</u><u> </u><u>the </u><u>parallel </u><u>sides </u><u>are </u><u>of </u><u>measure </u><u>1</u><u>3</u><u> </u><u>cm </u><u>and </u><u>2</u><u>5</u><u> </u><u>cm</u>
- To find - <u>Area </u><u>of </u><u>trapezium</u>
Refer the figure attached ~
In the given figure ,
AB = 25 cm
BC = AD = 15 cm
CD = 13 cm
<u>Construction</u><u> </u><u>-</u>
Now , we can clearly see that AECD is a parallelogram !
AE = CD = 13 cm
Now ,
Now , In ∆ BCE ,
Now , by Heron's formula
Also ,
<u>Since </u><u>we've </u><u>obtained </u><u>the </u><u>height </u><u>now </u><u>,</u><u> </u><u>we </u><u>can </u><u>easily </u><u>find </u><u>out </u><u>the </u><u>area </u><u>of </u><u>trapezium </u><u>!</u>
hope helpful :D
Answer:
B. A cow of 5 years is predicted to produce 5.5 more gallons per week.
Step-by-step explanation:
Let , where is the age of the dairy cow, measured in years, and is the predicted milk production, measured in gallons per week.
Besides, we consider and , such that , we define the difference between predicted milk productions () below:
(1)
If we know that and , then the difference between predicted milk productions is:
That is, a cow of 5 years is predicted to produce 5.5 more gallons per week than a cow of 10 years. Hence, the right answer is B.