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wlad13 [49]
3 years ago
8

The slopes of perpendicular lines are

Mathematics
2 answers:
jeka943 years ago
5 0
The slopes of perpendicular lines are opposite and reciprocals.
Andrews [41]3 years ago
4 0
The slopes of perpendicular lines are both opposite and reciprocals.
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What is the equation of the line that goes through the points (4,-1) and<br> (2,3)?
Arturiano [62]

Answer:

<u>y = -2x + 7</u>

Explanation:

<em><u>y = mx + b</u></em>

<em><u /></em>

<em>m = slope</em>

<em>b = y-intercept</em>

<em>y = a given y coordinate</em>

<em>x = a corresponding x coordinate</em>

<em />

First, we need to find the slope (m).

1) (4, -1)

2) (2/3)

m = slope = \frac{y_2-y_1}{x_2-x_1} = \frac{3-(-1)}{2-4} = \frac{4}{-2} = -2

plug in the values to the equation <u>y = mx + b</u>

<u />

-1 = -2(4) + b

-1 = -8 + b

7 = b

now, we can substitute in m and b into the equation y = mx + b

<u><em>y = -2x + 7</em></u>

5 0
3 years ago
To find solutions of equations should we look for x-intercepts or y-intercepts in a graph
Vladimir [108]
No one is going to be a great way to start a
3 0
2 years ago
Read 2 more answers
(-2,-7) and (7,-7) <br> What slope
Zarrin [17]

Answer:

Step-by-step explanation:

In order to find the slope, subtract -7 and -7, which is -7-(-7)=-7+7=0

Then subtract 7 and -2, which is 7-(-2) = 7+2=9

Divide 0 and 9 which equals 0

the slope is 0

3 0
3 years ago
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What is the length of the hypotenuse
podryga [215]
Pythagoras’ Theorem = a^2+b^2=c^2

c^2= 5^2+12^2
=25+144
=169

c= sqrt of 169
c=13

Hypotenuse=13cm
7 0
3 years ago
Read 2 more answers
Find the midpoint of the segment between the points (8,−10) and (−10,−8) A. (−1,−9) B. (0,−6) C. (0,0) D. (−1,2)
Degger [83]

Answer:

Hey there!

We can use the midpoint formula to find that the midpoint is (-1, -9).

Let me know if this helps :)

4 0
3 years ago
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