Question

Which expression can be simplified as 1/18n? (n2)9. (n^-9)-2. (n^-6)-3. (n^-6)-3. (n-3)^6

Answer 1

Answer:

$\frac{1}{n^{18}} = (n^{-3})^6$

Step-by-step explanation:

Given

$\frac{1}{n^{18}}$

Required

Determine its equivalent

$\frac{1}{n^{18}}$

Express 18 as 3 * 6

$\frac{1}{n^{18}} = \frac{1}{(n^{3})^6}$

This can be rewritten as:

$\frac{1}{n^{18}} = (\frac{1}{n^{3}})^6$

Apply the following law of indices:'

$\frac{1}{a^b} = a^{-b}$

$\frac{1}{n^{18}} = (n^{-3})^6$

Hence;

(d) is correct