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3 years ago

Can somebody help me please

Mathematics

1 answer:

lisabon 2012 [21]3 years ago

5 0

Answer:

Step-by-step explanation:

a - 7 = 3(b + 2)

a - 7 = 3b + 2*3

a - 7 = 3b + 6 {Subtract 6 from both sides}

a - 7 - 6 = 3b

a - 13 = 3b {Divide both sides by 3}

$b =\frac{a-13}{3}$

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Y equals the quotient of the quantity x squared plus 4 times x and the quantity x cubed minus 5.

koban [17]

Given:

Consider the completer question is "Find the derivative $\dfrac{dy}{dx}$ for $y=\dfrac{x^2-4x}{x^3-5}$ ."

To find:

The derivative $\dfrac{dy}{dx}$ .

Solution:

Chain rule: $\dfrac{d}{dx}f(g(x))=f'(g(x))\cdot g'(x)$

Quotient rule: $\dfrac{d}{dx}\dfrac{f(x)}{g(x)}=\dfrac{g(x)f'(x)-f(x)g'(x)}{[g(x)]^2}$

We have,

$y=\dfrac{x^2-4x}{x^3-5}$

Differentiate with respect to x.

$\dfrac{dy}{dx}=\dfrac{d}{dx}\left(\dfrac{x^2-4x}{x^3-5}\right)$

Using chain rule and quotient rule, we get

$\dfrac{dy}{dx}=\dfrac{(x^3-5)\dfrac{d}{dx}(x^2-4x)-(x^2-4x)\dfrac{d}{dx}(x^3-5)}{(x^3-5)^2}$

$\dfrac{dy}{dx}=\dfrac{(x^3-5)(2x-4)-(x^2-4x)(3x^2)}{(x^3-5)^2}$

$\dfrac{dy}{dx}=\dfrac{2x^4-4x^3-10x+20-3x^4+12x^3}{(x^3-5)^2}$

$\dfrac{dy}{dx}=\dfrac{-x^4+8x^3-10x+20}{(x^3-5)^2}$

Therefore, the required answer is $\dfrac{dy}{dx}=\dfrac{-x^4+8x^3-10x+20}{(x^3-5)^2}$ .

4 0

3 years ago

Add 7 and p, then divide 4 by the result

Dima020 [189]

Answer:

(7+p)/4

Step-by-step explanation:

(7+p)/4

5 0

3 years ago

Mathematics (Reasked) Thank you for any answers, please be sure of it before you respond.

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3 years ago

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pashok25 [27]

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5 0

3 years ago

Read 2 more answers

Jacob made a banner for a sporting event in the shape of a parallelogram. The area of the banner is 127 1/2 square centimeters.

MAVERICK [17]

Answer:30

Step-by-step explanation: its 30 because you divide 127 1/2 or 127.5 by 4.25 or 4 1/4.

4 0

3 years ago

Can somebody help me please ​

Can somebody help me please