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Naya [18.7K]
3 years ago
8

Given a circle with a radius of 22 inches, what is the circumference in terms of π?

Mathematics
2 answers:
Mars2501 [29]3 years ago
5 0

Answer:

circumference = 2\pi \: r \\  = 2 \times \pi \times 22 \\  = 44\pi \: inches

saw5 [17]3 years ago
3 0

Answer:

The circumference is 44 pi.

Step-by-step explanation:

You have to use the formula, C=2 Pi R but since it's in terms of pi, we can not include pi in the equation. 2 times r (radius) is 44, therefor the answer is 44 pi.

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Find all the zeros of the polynomial function p(x) = x3 – 5x2 + 33x – 29
hram777 [196]

Answer:

\large \boxed{\sf \ \ x=1, \ \ x=2+5i, \ \ x=2-5i \ \ }

Step-by-step explanation:

Hello,

I assume that we are working in \mathbb{C}, otherwise there is only one zero which is 1. Please consider the following.

First of all, <u>we can notice that 1 is a trivial solution</u> as

   p(1) = 1^3-5\cdot 1^2 + 33\cdot 1-29=1-5+33-29=0

It means that (x-1) is a factor of p(x) so we can find two real numbers, a and b, so that we can write the following.

p(x)=(x-1)(x^2+ax+b)=x^3+ax^2+bx-x^2-ax-b=x^3+(a-1)x^2+(b-a)x-b

Let's identify like terms as below.

a-1 = -5 <=> a = -5 + 1 = -4

b-a = 33

-b = -29 <=> b = 29

So

\boxed{ \ p(x)=(x-1)(x^2-4x+29) \ }

Now, we need to find the zeroes of the second factor, meaning finding x so that:

x^2-4x+29=0 \ \text{ complete the square, 29 = 25 + 4}  \\ \\  x^2-2\cdot 2 \cdot x+2^2+25=0 \\ \\ (x-2)^2=-25=(5i)^2 \ \text{ take the root } \\ \\x-2=\pm 5i \ \text{ add 2 } \\ \\  x = 2+5i \ \text{ or } \ x = 2-5i

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

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soldi70 [24.7K]

Answer:

the 3rd one is the graph answer

6 0
3 years ago
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