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Kitty [74]
3 years ago
15

PLEASE HELP WILL MARK BRAINLIEST

Mathematics
2 answers:
musickatia [10]3 years ago
8 0
First, determine the blueberries needed for only 1/3 cup of jam
for 1/3 cup = for 2/3 cup ÷ 2
for 1/3 cup = 3/4 ÷ 2
for 1/3 cup = 3/4 × 1/2
for 1/3 cup = 3/8
We need 3/8 pounds of blueberries for 1/3 cup of jam

Second, determine the blueberries needed for a cup of jam
a cup means 3/3 cup, so the blueberries needed will be
for 3/3 cup = for 1/3 cup × 3
for 3/3 cup = 3/8 × 3
for 3/3 cup = 9/8

Change it to mixed fraction
9/8 = 1 1/8
For a cup of jam we need 1 1/8 pounds of blueberries
The answer is first option
egoroff_w [7]3 years ago
3 0
Option 4 is the correct answer
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Answer:

e=\frac{1}{4} fg

Step-by-step explanation:

Joint variation problem  solve using the equation y = kxz.

e ∝ fg

e=kfg

now substitute the values

4=k*2*8\\4=16k\\k=\frac{4}{16} \\k=\frac{1}{4}

The relationship will be:

e=kfg\\e=\frac{1}{4} fg

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Answer:

\begin{array}{cccccc}{x} & {V} & {W} & {X} & {Y} & {Z} & P(x) & {0.20} & {0.20} & {0.20} & {0.20} & {0.20} \ \end{array}

Step-by-step explanation:

Given

S = \{V,W,X,Y,Z\}

n(S) = 5

Required

The probability model

To do this, we simply calculate the probability of each container.

So, we have:

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P(W) = \frac{n(W)}{n(S)} = \frac{1}{5} = 0.20

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P(Y) = \frac{n(Y)}{n(S)} = \frac{1}{5} = 0.20

P(Z) = \frac{n(Z)}{n(S)} = \frac{1}{5} = 0.20

So, the probability model is:

\begin{array}{cccccc}{x} & {V} & {W} & {X} & {Y} & {Z} & P(x) & {0.20} & {0.20} & {0.20} & {0.20} & {0.20} \ \end{array}

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Step-by-step explanation:

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