1.
If no changes are made, the school has a revenue of :
625*400$/student=250,000$
2.
Assume that the school decides to reduce n*20$.
This means that there will be an increase of 50n students.
Thus there are 625 + 50n students, each paying 400-20n dollars.
The revenue is:
(625 + 50n)*(400-20n)=12.5(50+n)*20(20-n)=250(n+50)(20-n)
3.
check the options that we have,
a fee of $380 means that n=1, thus
250(n+50)(20-n)=250(1+50)(20-1)=242,250 ($)
a fee of $320 means that n=4, thus
250(n+50)(20-n)=250(4+50)(20-4)=216,000 ($)
the other options cannot be considered since neither 400-275, nor 400-325 are multiples of 20.
Conclusion, neither of the possible choices should be applied, since they will reduce the revenue.
Answer:
5x + 1 is the simplest form
Step-by-step explanation:
what is equivalent to 10x - (5x -1)
10x - (5x -1) = 10x - 5x + 1
= 5x + 1
Answer:
its 15 lol
this is elementary school or something???
Step-by-step explanation:
IF
3 * x =9
then do 9/3=3
So you are multiplying by 3
So therefore you would do that to 5 so its 9/15
and 9/15 and 3/5 are the same, just that 9/15 isnt simplified
hope this helps have a nice day!!
Answer:
10 ,16 AND 8
Step-by-step explanation:
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