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2 years ago

The question is in the photo. it is asking for 2 answers

Mathematics

1 answer:

Alex777 [14]2 years ago

7 0

9514 1404 393

Answer:

2nd force: 99.91 lb
resultant: 213.97 lb

Step-by-step explanation:

In the parallelogram shown, angle B is the supplement of angle DAB:

∠B = 180° -77°37' = 102°23'

Angle ACB is the difference of angles 77°37' and 27°8', so is 50°29'.

Now, we know the angles and one side of triangle ABC. We can use the law of sines to solve for the other two sides.

BC/sin(A) = AB/sin(C)

AD = BC = AB·sin(A)/sin(C) = (169 lb)sin(27°8')/sin(50°29') ≈ 99.91 lb

AC = AB·sin(B)/sin(C) = (169 lb)sin(102°23')/sin(50°29') ≈ 213.97 lb

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$\bold{\huge{\underline{ Solution\: 2 }}}$

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$\sf{\underline{= {\angle} IHJ }}$
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$\bold{\huge{\underline{ Solution\: 3 }}}$

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