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jek_recluse [69]
3 years ago
8

76,80,88,95,100,101,? Which number comes next in this sequence?

Mathematics
2 answers:
LenaWriter [7]3 years ago
8 0
The number that comes next In the sequence is 112.
ANTONII [103]3 years ago
3 0

Answer:

112

Step-by-step explanation:

76->88->100->112

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9+3.5g=11-0.5g solve for g
Tanzania [10]

Answer:

g = 1/2

Step-by-step explanation:

Step 1: Add 0.5g to both sides

9 + 4g = 11

Step 2: Subtract 9 from both sides

4g = 2

Step 3: Divide by 4 on both sides

g = 2/4

Step 4: Simplify

g = 1/2

5 0
3 years ago
Read 2 more answers
I need help on this question
Eva8 [605]

Answer:

4x5

Step-by-step explanation:

6 0
3 years ago
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there are 60 teams attend a chess tournament. every team will play with every other team exactly once. Supposed each team has a
Karolina [17]

The probability that no two teams win the same number of games, P ≈ 2.084 × 10⁻⁴⁵³

The reason for arriving at the above probability is as follows:

The given parameters are;

The number of teams in the tournament, n = 60

The chance of a team winning a game = 50% = 0.5

The number of ties = No ties

The required parameter:

The probability that no two teams win the same number of games

Method:

Calculate the number of ways no two teams win the same number of games, and divide the result by the total number of possible outcomes

Solution:

The number of matches played, n = \dbinom {60} {2} = 1,770

The possible outcomes = 2; Winning or losing

The total number of possible outcomes, n_p = 2¹⁷⁷⁰

The number of games won by each team is between 0 and 59

The ways in which no two teams won the same number of games is given by the games won by the teams to be 0, 1, 2,..., 57, 58, 59

Therefore, the number of ways no two teams won the same number of games, the required outcomes, n_k = 59!

Probability = \dfrac{Number \ of \ possible \ outcomes}{Number \ of \ required\ outcomes}

The probability that no two teams win the same number of games is given as follows;

\mathbf{P(No \ two \ teams \ won \ the \ same \ number \ of \ games)} = \dfrac{n_k}{n_p}

Therefore;

P(No \ two \ teams \ won \ the \ same \ number \ of \ games) = \dfrac{59!}{2^{1,770}} \approx \mathbf{2.084 \times 10^{-453}}

The probability that no two teams win the same number of games, P ≈ 2.084 × 10⁻⁴⁵³

Learn more about probability theory here:

brainly.com/question/1539712

3 0
3 years ago
Sandra is showing her work in simplifying (3.3 − 4.2) − 2.8 + 5.7. Identify any error in her work or reasoning. Step 1: (3.3 − 4
julsineya [31]
The answer is correct 
but I think in step 2 that should read the Associative property
8 0
3 years ago
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What is the colon form? :)​
Ann [662]

Answer and Step-by-step explanation:

I think this is correct? The directions aren't very clear/descriptive, so sorry if this is wrong.

A.

1. wins:games

2. wins:losses

3. losses:wins

4. games played:wins

5. losses:games played

B.

1. 8:12, or 2:3

2. 3:7

3. 5:3

4. 12:15, or 4:5

5. 20:25, or 4:5

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

4 0
3 years ago
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