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2 years ago

6

Which shows only a vertical translation? A triangle is translated to the right. A triangle is translated upwards. A triangle is

translated diagonally.

2 answers:

mojhsa [17]2 years ago

4 0

Answer:

b

Step-by-step explanation:

Ilia_Sergeevich [38]2 years ago

3 0

Answer:

The second graph is correct

Step-by-step explanation:

i jus put dat and it was correct

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10. Both x and y vary inversely with each other. When x is 10, y is 6,which of the following is not a possible pair of correspon

elena55 [62]

9514 1404 393

Answer:

D) 45 and 1.2

Step-by-step explanation:

The "varies inversely" relationship is described by the equation ...

y = k/x . . . . . . y varies inversely with x (and vice versa)

The value of k can be found from known values of x and y:

xy = k . . . . . . multiply the above equation by x

(10)(6) = k = 60 . . . . using the given values

__

To check if a given pair of numbers satisfies ...

y = 60/x

you can multiply them together to see if the product is 60.

(A) 12×5 = 60

(B) 15×4 = 60

(C) 25×2.4 = 60

(D) 45×1.2 = 54 . . . . . not a possible pair of corresponding values.

45 and 1.2 are not a possible solution for x and y.

8 0

2 years ago

Can someone explain how to factor a number like in the picture I attached? Thank you!

xenn [34]

hey man im sorry i just need points because im strugling

Step-by-step explanation:

5 0

2 years ago

In the center of town there is a square park with an area of 900 square feet. If Stephen walks from one corner of the park to th

Vedmedyk [2.9K]

The distance walked by Stephen is 42.42 feet

<h3><u>Solution:</u></h3>

Given that In the center of town there is a square park with an area of 900 square feet

Stephen walks from one corner of the park to the opposite corner

To find: Distance walked by Stephen

We need to find the distance that the person walk from one corner of the park to the opposite corner.

So, we need to find the Diagonal of the square park

<em><u>The diagonal of square is given as:</u></em>

$\text{ Diagonal } = \sqrt{2} \times \text{ side}$

Let us find the length of side of square

Given area of square = 900 square feet

<em><u>The area of square is given as:</u></em>

$area = (side)^2\\\\900 = (side)^2$

Taking square root on both sides,

$side = \sqrt{900} \\\\side = 30$

Thus length of each side of square is 30 feet

<em><u>Therefore, length of diagonal is given as:</u></em>

$diagonal = \sqrt{2} \times 30\\\\diagonal = 1.414 \times 30 = 42.42$

Hence, the distance that the person walks 42.42 feet

3 0

3 years ago

Write one sine and one cosine equation for each graph below.

pychu [463]

Answer:

Q13. y = sin(2x – π/2); y = - 2cos2x

Q14. y = 2sin2x -1; y = -2cos(2x – π/2) -1

Step-by-step explanation:

Question 13

(A) Sine function

y = a sin[b(x - h)] + k

y = a sin(bx - bh) + k; bh = phase shift

(1) Amp = 1; a = 1

(2) The graph is symmetrical about the x-axis. k = 0.

(3) Per = π. b = 2

(4) Phase shift = π/2.

2h =π/2

h = π/4

The equation is

y = sin[2(x – π/4)} or

y = sin(2x – π/2)

B. Cosine function

y = a cos[b(x - h)] + k

y = a cos(bx - bh) + k; bh = phase shift

(1) Amp = 1; a = 1

(2) The graph is symmetrical about the x-axis. k = 0.

(3) Per = π. b = 2

(4) Reflected across x-axis, y ⟶ -y

The equation is y = - 2cos2x

Question 14

(A) Sine function

(1) Amp = 2; a = 2

(2) Shifted down 1; k = -1

(3) Per = π; b = 2

(4) Phase shift = 0; h = 0

The equation is y = 2sin2x -1

(B) Cosine function

a = 2, b = -1; b = 2

Phase shift = π/2; h = π/4

The equation is

y = -2cos[2(x – π/4)] – 1 or

y = -2cos(2x – π/2) - 1

6 0

3 years ago

Please answer this question !! Thank u tons !! Will give brainliest !!

Anastaziya [24]

Answer: D

Step-by-step explanation:

The key to finding the line perpendicular to the one given is teh slope. The slope is the opposite reciprocal of the original line.

m=3

perpendicular m=-1/3

Now that we know the slope, we can see which of our answer choices have -1/3 as the slope. We can see D is the only option that has -1/3 for slope.

3 0

3 years ago

Read 2 more answers