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pychu [463]
3 years ago
10

Which biome receives the most rain?

Biology
2 answers:
Lena [83]3 years ago
3 0

Answer:

tropical rain forest

Setler [38]3 years ago
3 0

Answer:

tropical rainforest

Explanation:

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The domestic cat genome contains 2.9×109 base pairs. The length of linker DNA in mammals is 50 base pairs. Approximately how man
IgorLugansk [536]

Answer:

Number of nucleosomes in 2.9 * 10^9bp is equal to 1.47 * 10^7

Explanation:

For wounding one nucleosome, total length of DNA required is equal to 146 bp

The length of  linker DNA in mammals is equal to 50 bp

Thus , the total length of DNA that confides between two nucleosome is equal to the sum of wounding length of DNA and the linker length

= 146 + 50\\= 196bp

Thus, in 196bp length of DNA, the total number of nucleosomes is equal to 1

Thus, number of nucleosomes in 2.9 * 10^9bp is equal to

\frac{2.9* 10^9}{196} \\1.47 * 10^7

8 0
3 years ago
What sound frequency would a human ear not be able to detect?
CaHeK987 [17]

All of the are false lowest it can be without a human ear picking up is 19 hertz

4 0
3 years ago
Read 2 more answers
What is the fossil connection between Indohyus and the whale? What is the function of this bone? Why do you think these mammals
marysya [2.9K]

Answer:

Indohyus is a fossil, found in 2007, of a chevrotain-like mammal believed by some paleontologists in the Evil Liberal Science Conspiracy to be a transitional form between land-dwelling mammals and the ancestor of whales.

The origin of cetaceans from land-living mammals is among the most famous of these events. Much earlier, during the Mesozoic Era, many reptile groups also moved from land to wate

Explanation:

8 0
2 years ago
Read 2 more answers
How do you write an expression for "the product of 11 and w."?
yarga [219]
11w
11(w)
11×w
that a few different ways
4 0
3 years ago
Dihybrid crosses
Darina [25.2K]

Explanation:

The phenotypes and genotypes of the progeny can be determined by a dihybrid cross of the parents.

The heterozygous male will have the genotype 'SSww' and the heterozygous female will have the genotype 'ssWW'.

When crossed, the F1 offsprings will have a hybrid genotype of 'SsWw'. These offsprings are heterozygous with spotted skin and wooly hair.

On self-crossing of the F1 hybrids, we find four different combinations of the alleles- SW, Sw, SW and sw. The probability of getting each of these combinations is 1/4.

Hence, the probability of any dihybrid type is 1 out of the 16 possible genotypes. Using Punnet square, we find

9 SSWW: 3 SSww: 3 ssWW : 1 ssww

This is the phenotypic ratio of the offsprings.

The ratio of the possible genotypes will be 1:2:1:2:4:2:1:2:1.

8 0
2 years ago
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