After all this info you have given me, the correct one is Keystone species. As defined in sources like National Geographic, <span> These are types of plants or animals that play a unique and crucial role in the way an ecosystem functions. Without </span>keystone species<span>, the ecosystem would be dramatically different or cease to exist altogether. I hope this helps you a lot </span>
Answer:
The correct answer is: C) E,A,B,D,C.
Explanation:
Bone fractures occur when a trauma generated a breach in the continuity of the bone. When a bone fractures, a process called secondary healing starts.
The first step in fracture repair is the removal of dead tissues - this is done by specialized cells called phagocytes and osteoclasts, that proceed by "eating" the damaged tissues.
Next, a hematoma forms because the blood vessels surrounding the fractured bone were ruptured. This hematoma clots and forms the temporary frame for the process of healing that is happening.
Mesenchymal stem cells migrate to the area and begin to differentiate into fibroblasts and chondroblasts, which is important for the production of fibrocartilage, a tissue that will connect the ends of the broken bone.
Then, osteoprogenitor cells differentiate into osteoblasts, which are the cells that synthesize bone tissue. These osteoblasts will produce spongy bone. The newly-formed fibrocartilage tissue becomes calcified.
Finally, osteoclasts begin with a process called resorption, which consists of resorbing the dead portions of the new bony area. This resorption is coupled with osteoblasts' bone synthesis. These two processes that occur together are fundamental for bone remodeling, which will end up with the spongy bone being transformed into compact bone.
Answer:
E) Either anaphase I or II
Explanation:
Failure of segregation of homologous chromosomes during anaphase I or failure of segregation of sister chromatids during anaphase II leads to the presence of the abnormal number of chromosomes in resultant gametes. In the given example, the egg mother cell with 48 chromosomes (24 pairs) would enter meiosis I but the failure of one pair of homologous chromosomes to segregate from each other followed by normal meiosis II would result in the formation of two gametes with one extra chromosome and two gametes with one less chromosome.
On the other hand, if the nondisjunction occurs at anaphase II of meiosis II, two normal gametes, one gamete with one extra chromosome and one gamete with one less chromosome will be formed. Therefore, nondisjunction at anaphase I or anaphase II would have resulted in the production of eggs with one extra chromosome.