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olya-2409 [2.1K]
4 years ago
11

there are 1800 gym members in total. 3/4 are aged 25-59, 1/5 are over 60 and the remainder are under 25 years. how many members

are under 25?
Mathematics
1 answer:
Tresset [83]4 years ago
6 0
I could be wrong. Just saying.
1800*3/4=1,350
1800*1/5=360
1,350+360=1,710
1,800-1,710=90

I'm not an expert.
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Yes   you always do.

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8 0
3 years ago
Given m<12= 121 and m<6= 75, find the measure of each missing angle.
slava [35]

Answer/Step-by-step explanation:

Given:

m<12 = 121°

m<6 = 75°

a. m<1 = m<6 (vertical angles)

m<1 = 75° (substitution)

b. m<12 = m<1 + m2 (alternate exterior angles)

121° = 75° + m<2 (substitution)

121° - 75° = m<2 (subtraction property of equality)

46° = m<2

m<2 = 46°

c. m<1 + m<2 + m<3 = 180° (angles on a straight line)

75° + 46° + m<3 = 180° (substitution)

121° + m<3 = 180°

m<3 = 180° - 121° (subtraction property of equality)

m<3 = 59°

d. m<4 = m<3 (vertical angles)

m<4 = 59° (substitution)

e. m<5 + m<4 + m<6 = 180° (angles on a straight line)

m<5 + 59° + 75° = 180° (substitution)

m<5 + 134° = 180°

m<5 = 180° - 134° (Subtraction property of equality)

m<5 = 46°

f. m<7 = m<12 (vertical angles)

m<7 = 121° (substitution)

g. m<8 = m<4 (vertical angles)

m<8 = 59° (substitution)

h. m<9 = m<6 (Alternate Interior Angles)

m<9 = 75° (substitution)

i. m<10 + m<9 = 180° (Linear Pair)

m<10 + 75° = 180° (substitution)

m<10 = 180° - 75° (Subtraction property of equality)

m<10 = 105°

j. m<11 = m<8 (vertical angles)

m<11 = 59° (substitution)

k. m<13 = m<10 (vertical angles)

m<13 = 105° (substitution)

l. m<14 = m<9 (vertical angles)

m<14 = 75° (substitution)

5 0
3 years ago
Find the value of n that makes equation true.<br> 5n =20<br> n + 5 = 10<br> 2n = 3<br> n + 5 = 13
Kamila [148]

Answer:

n+5=10

Step-by-step explanation:

8 0
3 years ago
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27

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In an intro stats class, 57% percent of students eat breakfast in the morning and 80% of students floss their teeth. Forty-six p
WINSTONCH [101]

Answer: B. 11%

Step-by-step explanation:

Let A = Event that students eat breakfast in the morning.

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Now, the probability that a student from this class eats break feast but does not floss their teeth :-

P(A-B)=P(A)-P(A\cap B)\\\\ = 0.57-0.46=0.11=11\%

Hence, the probability that a student from this class eats break feast but does not floss their teeth= 11%

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3 years ago
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