Answer:
Step-by-step explanation:

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➷ final = original x multiplier^n
n is the number of years
Substitute the values in:
final = 3800 x 1.054^3
final = 4449.440763
The closest answer is A
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If a polynomial with real coefficient has a complex zero, the conjugate of that number will be a zero as well.
So, if 4-6i is a zero, 4+6i will be a zero as well
If -2+11i is a zero, -2-11i will be a zero as well
So, the zeroes are

the answer would be a or b. Turn on verified mode for professionals to answer)
Assuming the order required is as n-> inf.
As n->inf, o(log(n+1)) -> o(log(n)) since the 1 is insignificant compared with n.
We can similarly drop the "1" as n-> inf, the expression becomes log(n^2+1) ->
log(n^2)=2log(n) which is still o(log(n)).
So yes, both are o(log(n)).
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