Mass of the car = 1200 kg
Mass of the truck = 2100 kg
Total mass of car and truck = 2100 + 1200 = 3300 kg
Since, the car pushes the truck. Hence, they will move together and will have same acceleration.
Let the acceleration be a.
According to Newton's second law:
F(net) = ma
F = 4500 N
4500 = 3300 × a
a = 1.36 m/s^2
Let the force applied by the car on truck be F.
F = F(net) on the truck
F = ma
F = 2100 × 1.36
F = 2856 N
Hence, the force applied by the car on the truck is 2856 N
Answer:
by obtaining the total mass of the dimes present:
d = 27.22 g / dozen the density of dimes
M = n * d = 5 dozen * 27.22 g / dozen = 126.1 g
By bring their legs close to their bodies, they are decreasing the length of the pendulum which help them move more quickly.
A pendulum is nothing but a body suspended from a fixed point so that it can swing back and forth under the influence of gravity.
Here in this case Gibbons are bringing their legs close to their bodies and reducing the length of the pendulum. Since as the length of the pendulum increases the speed of the movement will be reduced. By bringing their legs close to their bodies they are reducing the length and in turn their speed increase and they move quickly.
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Answer:
1.26 m/s²
Explanation:
Given:
Δx = 172 m
v₀ = 17.3 m/s
v = 27.1 m/s
Find: a
v² = v₀² + 2aΔx
(27.1 m/s)² = (17.3 m/s)² + 2a (172 m)
a = 1.26 m/s²
