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AfilCa [17]
3 years ago
13

The chemical reaction involved in burning wood is that endothermic or Exothermic?

Physics
1 answer:
kari74 [83]3 years ago
3 0
Its Exothermic.......
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A simple model of a hydrogen atom is a positive point charge +e (representing the proton) at the center of a ring of radius a wi
Norma-Jean [14]

Answer:

Now e is due to the ring at a

So

We say

1/4πEo(ea/ a²+a²)^3/2

= 1/4πEo ea/2√2a³

So here E is faced towards the ring

Next is E due to a point at the centre

So

E² = 1/4πEo ( e/a²)

Finally we get the total

Et= E²-E

= e/4πEo(2√2-1/2√2)

So the direction here is away from the ring

8 0
3 years ago
A vector has a magnitude of 46.0 m and points in a direction 20.0° below the positive x-axis. A second vector, , has a magnitude
irina1246 [14]

Answer with Step-by -step explanation:

We are given that

b.\mid A\mid=46 m

\theta=20^{\circ} below the positive x-axis

Therefore, the angle made by vector A in counter clockwise direction when measure from positive x-axis=x=360-20=340^{\circ}

x-component of vector A=A_x=\mid A\mid cosx=46cos 340=46\times 0.94=43.24

y-Component of vector A=A_y=\mid A\mid sinx=46sin340=46(-0.34)=-15.64

Magnitude of vector B=86 m

The vector B makes angle with positive x- axis=x'=42^{\circ}

x-component of vector B=B_x=86cos42=63.64

y-Component of vector B=B_y=86sin42=57.62

Vector A=A_xi+A_yj=43.24i-15.64j

Vector B=B_xi+B_yj=63.64i+57.62j

Vector C=A+B

Substitute the values

C=43.24i-15.64j+63.64i+57.62j

C=106.88i+41.98j

c.Direction=\theta=tan^{-1}(\frac{y}{x})=tan^{-1}(\frac{41.98}{106.88})=21.5^{\circ}

The direction of the vector C=21.5 degree

6 0
3 years ago
Part A.)Six boxes held at rest against identical walls.
krok68 [10]

Answer:

Explanation:

When a body is held against a vertical wall , to keep them in balanced position , normal force is applied on their surface . this force creates normal reaction which acts against the normal force and it is equal to the normal force as per newton's third law . Ultimately friction force is created which is proportional to normal force and it acts in vertically upward direction . It prevents the body from falling down .

Hence normal force = reaction force .

From second law also net force is zero , so if  normal force is N and reaction force is R

R - N = mass x acceleration = mass x 0 = 0

R = N .

Ranking normal force from  highest  to smallest

150 N , 130 N , 120 N

B )

Frictional force is equal to the weight of the body because the body is held at rest .

Ranking of frictional force form largest to smallest

7 kg , 5 kg , 3 kg , 1 kg .

Here frictional force is irrespective of the normal force acting on the body  because frictional force adjusts itself so that it becomes equal to weight in all cases here because it always balances the weight of the body .

6 0
3 years ago
Which student is doing work?
Vilka [71]

Answer:

d

hope this helps

Explanation:

8 0
3 years ago
Read 2 more answers
Calculate the work done if a boy lifts a bag of cement 500N to the floor of a lorry 2.5m above the ground
eduard

Answer:

W = 1250 J = 1.25 KJ

Explanation:

The work done by the boy is due to the change in the position of the cement vertically. Hence, the work done in this case will be equal to the potential energy of the cement:

W = P.E\\W = mgh

where,

W = Work done = ?

mg = W = weight of cement = 500 N

h = height covered = 2.5 m

Therefore,

W = (500\ N)(2.5\ m)

<u>W = 1250 J = 1.25 KJ</u>

4 0
3 years ago
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