7500J
Explanation:
Given parameters:
Weight of child = 150N
Height of lifting = 50m
Distance = 50m
Unknown:
Work done by the woman = ?
Solution:
Work done by a body is the force applied to move a body through a given distance.
Work done = Force x distance
Weight is a force impacted by the mass of a body and the gravity on it.
input the parameters:
Work done = 150 x 50 = 7500J
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Answer:
a. 86.80 m
b. i. The mass of the bob
ii. The length of the pendulum
Explanation:
a. Determine the height of the smokestack.
Using T = 2π√(L/g) where T = period of pendulum = 18.7 s, L = length of pendulum = height of smokestack and g = acceleration due to gravity = 9.8 m/s².
So, making L subject of the formula, we have
T = 2π√(L/g)
T/2π = √(L/g)
squaring both sides, we have
(T/2π)² = L/g
L = (T/2π)²g
Substituting the values of the variables into the equation, we have
L = (T/2π)²g
L = (18.7 s/2π)²(9.8 m/s²)
L = (2.976 s)²(9.8 m/s²)
L = 8.857 s² × 9.8 m/s²
L = 86.796 m
L ≅ 86.80 m
b. What factors influence the period of a simple pendulum
The factors that influence the period of a simple pendulum are
i. The mass of the bob
ii. The length of the pendulum
let Coefficients of Friction of Rubber on asphalt (dry) =0.7
F= Coefficients of Friction * normal force = 0.7 * 60 =42 N
so the net force of the rubber is zero, meaning it will travel at a constant speed.
When the rubber is travel at 2m/s, 42N is required to keep moving at constant speed
Answer:
Speed of the helium after collision = 246 m/s
Explanation:
Given that
Mass of helium ,m₁ = 4 u
u₁=598 m/s
Mass of oxygen ,m₂ = 32 u
u₂ = 401 m/s
v₂ =445 m/s
Given that initially both are moving in the same direction and lets take they are moving in the right direction.
Speed of the helium after collision = v₁
There is no any external force on the masses that is why the linear momentum will be conserve.
Initial linear momentum = Final linear momentum
P = m v
m₁u₁+m₂u₂ = m₁v₁+m₂v₂
598 x 4 + 32 x 401 = 4 x v₁+ 32 x 445
v₁ = 246 m/s
Speed of the helium after collision = 246 m/s
