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3 years ago

Which value for the variable w makes the value of this expression 10? 50/w

Mathematics

1 answer:

Lelechka [254]3 years ago

3 0

5
make me brainliest if the answer is correct, thank you in advance :)

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What Is the answer I am really struggling with fractions

Citrus2011 [14]

9/5 or 1 & 4/5 is the answer

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4 years ago

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normal population has a mean of 63 and a standard deviation of 13. You select a random sample of 25. Compute the probability tha

alexira [117]

Answer:

0.2207

Step-by-step explanation:

Here, we want to find the probability that the sample mean is greater than 25.

What we use here is the z-scores statistic

Mathematically;

z-score = (x-mean)/SD/√n

From the question;

x = 65, mean = 63, SD = 13 and n = 25

Plugging these values in the z-score equation, we have

Z-score = (65-63)/13/√25 = 2/13/5 = 0.77

So the probability we want to calculate is ;

P(z > 0.77)

This can be obtained from the standard normal distribution table

Thus;

P(z > 0.77) = 0.22065 which is 0.2207 to 4 d.p

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4 years ago

Which algebraic expression is a polynomial?

AlexFokin [52]

Answer:

the second option is the correct answer

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2 years ago

The figure is made up of a cylinder and a hemisphere. To the nearest whole number, what is the approximate volume of this figure

Novosadov [1.4K]

Hello!

The figure is made up of a cylinder and a hemisphere. To the nearest whole number, what is the approximate volume of this figure?

Use 3.14 to approximate π .

Enter your answer in the box. in.³

Data: (Cylinder)

h (height) = 7 in

r (radius) = 2.5 in (The diameter is 5 being twice the radius)

Adopting: $\pi \approx 3.14$

V (volume) = ?

Solving: (Cylinder volume)

$V = \pi *r^2*h$

$V = 3.14 *2.5^2*7$

$V = 3.14*6.25*7$

$V = 137.375 \to \boxed{V_{cylinder} \approx 137.38\:in^3}$

Note: Now, let's find the volume of a hemisphere.

Data: (hemisphere volume)

V (volume) = ?

r (radius) = 2.5 in (The diameter is 5 being twice the radius)

Adopting: $\pi \approx 3.14$

If: We know that the volume of a sphere is $V = 4* \pi * \dfrac{r^3}{3}$ , but we have a hemisphere, so the formula will be half the volume of the hemisphere $V = \dfrac{1}{2}* 4* \pi * \dfrac{r^3}{3} \to \boxed{V = 2* \pi * \dfrac{r^3}{3}}$

Formula: (Volume of the hemisphere)

$V = 2* \pi * \dfrac{r^3}{3}$

Solving:

$V = 2* \pi * \dfrac{r^3}{3}$

$V = 2*3.14 * \dfrac{2.5^3}{3}$

$V = 2*3.14 * \dfrac{15.625}{3}$

$V = \dfrac{98.125}{3}$

$\boxed{ V_{hemisphere} \approx 32.70\:in^3}$

Now, to find the total volume of the figure, add the values: (cylinder volume + hemisphere volume)

Volume of the figure = cylinder volume + hemisphere volume

Volume of the figure = 137.38 in³ + 32.70 in³

$Volume\:of\:the\:figure =170.08 \to \boxed{\boxed{\boxed{Volume\:of\:the\:figure = 170\:in^3}}}\end{array}}\qquad\quad\checkmark$

_______________________

I Hope this helps, greetings ... Dexteright02! =)

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3 years ago

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PLZ HELP ME I WAS STUCK ON THIS FOR 30 MINS WILL GIVE BRAINLIST

SVETLANKA909090 [29]

Answer:

Step-by-step explanation:

6^3 is the error, 6^3 is 216.

the correct volume is 904.32

4 0

3 years ago

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