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stealth61 [152]

3 years ago

15

A rectangular lot that is 60 feet by 80 feet has a straight diagonal path way. What is the length in feet of the diagonal path w

ay

1 answer:

Allisa [31]3 years ago

4 0

Hi everyone, I could say 60 times 80=480

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13 - r < 82<br><br><br><br><br> PLA I NEED THIS

maria [59]

Answer:

r > -69

Step-by-step explanation:

13 - r < 82

subtract 13 from both sides

13 - r - 13 < 82 - 13

- r < 69

to flip the inequality sign, multiply both side by -1 to make r positive:

- r (-1) < 69 (-1)

r > -69

5 0

2 years ago

Read 2 more answers

The obligation of a medical coder to keep patients' medical information confidential is an example of the theory of ethics. a) d

jolli1 [7]

I am 89% sure that it’s D

7 0

3 years ago

Find an equation of the line that satisfies the given conditions.

8090 [49]

Answer:

$x=8$

Step-by-step explanation:

Given:

The equation of the given line is $y=9$

A point on the unknown line is (8, 5).

The unknown line is perpendicular to the line $y=9$ .

A line of the form $y=a$ where 'a' is a constant is a line parallel to the x axis. The line has a constant value for 'y' irrespective of the value of 'x'. The slope of such lines are equal to 0. So, slope of the known line is 0.

Now, when two lines are perpendicular, the product of their slopes is -1.

Let the slope of the unknown line be 'm', then:

$m\times 0 =-1\\m=-\frac{-1}{0}=$ undefined.

Therefore, the slope of the unknown line is undefined. A line parallel to y axis has undefined slope. So, the equation of the unknown line is of the form:

$x=b$ where, 'b' is a constant and is equal to the abscissa (x value) of the line.

As per question, (8, 5) lies on this line. Therefore, the value of 'x' is 8.

So, the equation of the unknown line is $x=8$

8 0

4 years ago

Read 2 more answers

I am doing a math test and need help with this problem

pentagon [3]

Answer:

21√(5(

Step-by-step explanation:

6√(9*5)

6*3√(5)

18√(5) + 3√(5) = 21√(5(

7 0

3 years ago

) Determine the probability that a bit string of length 10 contains exactly 4 or 5 ones.

yanalaym [24]

Answer: 0.4512

Step-by-step explanation:

A bit string is sequence of bits (it only contains 0 and 1).

We assume that the 0 and 1 area equally likely to any place.

i.e. P(0)= P(1)= $\dfrac{1}{2}$

The length of bits : n = 10

Let X = Number of getting ones.

Then , $X \sim Bin(n=10,\ p=\dfrac{1}{2})$

Binomial distribution formula : $P(X=x)=^nC_x p^x q^{n-x}$ , where p= probability of getting success in each event and q= probability of getting failure in each event.

Here , $p=q=\dfrac{1}{2}$

Then ,The probability that a bit string of length 10 contains exactly 4 or 5 ones.

$P(X= 4\ or\ 5)=P(x=4)+P(x=5)\\\\=^{10}C_4(\dfrac{1}{2})^{10}+^{10}C_4(\dfrac{1}{2})^{10}$

$=\dfrac{10!}{4!6!}(\dfrac{1}{2})^{10}+\dfrac{10!}{5!5!}(\dfrac{1}{2})^{10}$

$=(\dfrac{1}{2})^{10}(\dfrac{10!}{4!6!}+\dfrac{10!}{5!5!})$

$=(\dfrac{1}{2})^{10}(210+252)$

$=(0.0009765625)(462)$

$=0.451171875\approx0.4512$

Hence, the probability that a bit string of length 10 contains exactly 4 or 5 ones is 0.4512.

3 0

4 years ago