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3 years ago

This circle centered at the origin and the Length of its radius is 8. What is the equation of the circle?

Mathematics

2 answers:

kondor19780726 [428]3 years ago

5 0

D.....all ......dots are to make 20 wordt

jeka943 years ago

3 0

The equation of the circle is always:
$(x - h)^{2} + (y-k)^{2} = r^{2}$
Where (h, k) is the center of the circle, r is the radius. So, the equation will be:
$x^{2} + y^{2} = 64$
Hope this helps! The answer is B.

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Which number has a 5 that represents a value ten times greater than the value represented by the 5 in 41,253 ?

Sergio039 [100]

Wouldn't the answer be any number which has the hundredths place as a 5? For example, 23,521.

As 50 x 10 = 500 and the 5 in 23,521 represents 500.

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2 years ago

In its monthly report, the local animal shelter states that it currently has 24 dogs and 18 cats available for adoption. Eight o

andrezito [222]

Answer with Step-by-step explanation:

We are given that

Total dogs=24

Total cats=18

Total animals=24+18=42

Male dogs=8

Male cats=6

Total male animals=8+6=14

Total female animals=42-14=28

Female cats=18-6=12

Dogs female=24-8=16

a.We have to find the probability that the pet is male, given that it is cat.

It means we have to find P(Male/cat)

Conditional probability: $P(A/B)=\frac{P(A\cap B)}{P(B)}$

P(Cat)= $\frac{18}{42}$

$P(male cat)=\frac{6}{42}$

$P(Male/cat)=\frac{\frac{6}{42}}{\frac{18}{42}}$

P(male/cat)= $\frac{6}{18}=0.33$

b. $P(female cat)=\frac{12}{42}$

$P(female)=\frac{28}{42}$

$P(Cat/Female)=\frac{\frac{12}{42}}{\frac{28}{42}}=\frac{12}{28}=0.43$

c.P(Dog)= $\frac{24}{42}$

$P(dog female)=\frac{16}{42}$

$P(female/dog)=\frac{\frac{16}{42}}{\frac{24}{42}}$

$P(female/dog)=\frac{16}{24}=0.67$

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3 years ago

Data set: 3,6,8,8,14,27 find mean median and range

maks197457 [2]

Answer:

Median is 8

Range is 24

Step-by-step explanation:

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3 years ago

Which matrix represents the system of equations shown?

kicyunya [14]

Answer:

by relation

$\binom{3x \: \: - 2y \: \: 12}{4x \: \: \: \: - y \: \: \: \: \: 9} \\ eliminate \: the \: unknowns \: (x \: and \: y) \\ \binom{3 \: \: - 2 \: \: 12}{4 \: \: \: \: - 1 \: \: \: \: \: 9}$

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3 years ago