Answer:
B & E
Step-by-step explanation:
Edge trust me
About $801.99 bc 603X.33 is 198.99 plus 603 is 801.99
Probability of passing history course = 0.59
Probability of passing math course = 0.60
Probability of passing both courses = 0.49
Probability of passing at least one = 0.59 + 0.60 - 0.49 = 0.7 ##
To solve this, set up two equations using the information you're given. Let's call our two numbers a and b:
1) D<span>ifference of two numbers is 90
a - b (difference of two numbers) = 90
2) The quotient of these two numbers is 10
a/b (quotient of the two numbers) = 10
Now you can solve for the two numbers.
1) Solve the second equation for one of the variables. Let's solve for a:
a/b = 10
a = 10b
2) Plug a =10b into the first equation and solve for the value of b:
a - b = 90
10b - b = 90
9b = 90
b = 10
3) Using b = 10, plug it back into one of the equations to find the value of a. I'll plug it back into the first equation:
a - b = 90
a - 10 = 90
a = 100
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Answer: The numbers are 100 and 10</span>
