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3 years ago

How would you compare two ratios given in words?

Mathematics

2 answers:

OlgaM077 [116]3 years ago

7 0

Answer:

Write the ratios as fractions. Then identify a common denominator. Rewrite the fractions using the common denominator. Compare the numerators. The greater numerator indicates the greater ratio.

Step-by-step explanation:

Solnce55 [7]3 years ago

6 0

Answer:

you turn them into fractions for example 3:4 and 7:9

put them as factions 3/5 and 7/9 and them find out wich fraction is the biggest.

Step-by-step explanation:

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Using the graph, select an answer.

saul85 [17]

Answer:

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Step-by-step explanation:

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3 years ago

20 POINTS AND BRAINIEST FOR THOSE WHO ANSWER CORRECTLY

Licemer1 [7]

Answer:

x^2 y ^4 ∛ [x^2 y ^2 ] is the answer that I got

Step-by-step explanation:

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3 years ago

Read 2 more answers

What is the quotient and the remainder for <br> 52 divided by 8

Marianna [84]

52/8 = 6
6*8 = 48
52-48 = 4

So 52 = 6*8+4

The quotient is 6, the remainder is 4.

5 0

3 years ago

If x > 1, then which of the following has the LEAST value?

jasenka [17]

What are the answers?

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3 years ago

Using the given information, give the vertex form equation of each parabola.

Amanda [17]

Answer:

The equation of parabola is given by : $(x-4) = \frac{-1}{3}(y+3)^{2}$

Step-by-step explanation:

Given that vertex and focus of parabola are

Vertex: (4,-3)

Focus:( $\frac{47}{12}$ ,-3)

The general equation of parabola is given by.

$(x-h)^{2} = 4p(y-k)$ , When x-componet of focus and Vertex is same

$(x-h) = 4p(y-k)^{2}$ , When y-componet of focus and Vertex is same

where Vertex: (h,k)

and p is distance between vertex and focus

The distance between two points is given by :

L= $\sqrt{(X2-X1)^{2}+(Y2-Y1)^{2}}$

For value of p:

p= $\sqrt{(X2-X1)^{2}+(Y2-Y1)^{2}}$

p= $\sqrt{(4-\frac{47}{12})^{2}+((-3)-(-3))^{2}}$

p= $\sqrt{(\frac{1}{12})^{2}}$

p= $\frac{1}{12}$ and p= $\frac{-1}{12}$

Since, Focus is left side of the vertex,

p= $\frac{-1}{12}$ is required value

Replacing value in general equation of parabola,

Vertex: (h,k)=(4,-3)

p= $\frac{-1}{12}$

$(x-h) = 4p(y-k)^{2}$

$(x-4) = 4(\frac{-1}{12})(y+3)^{2}$

$(x-4) = \frac{-1}{3}(y+3)^{2}$

8 0

3 years ago