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Oksi-84 [34.3K]
2 years ago
12

What is the solution of the linear-quadratic system of equations? { y = x 2 + 5 x − 3 y − x = 2

Mathematics
2 answers:
photoshop1234 [79]2 years ago
8 0

Try substituting those values, and you will see they do not fit either equation.

looking at the 2nd equation, y = x+2, so

x+2 = x^2+5x-3

x^2 + 4x - 5 = 0

(x+5)(x-1) = 0

x = -5 or 1

so, y = -3 or 3

the solutions are thus (-5,-3)(1,3)

Hope this helps

Please give me Brainliest

Alex2 years ago
7 0

Answer-

(-5,-3)(1,3)

How I got my answer-

×+2=×^2+5×-3

×^2+4×-5=0

(×+5)(×-1)=0

×= -5 or 1

and y=3 or 3

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Question<br> (X-5y/y3)-1=
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Answer:

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Step-by-step explanation:

Complete question

\frac{x - 5y}{y^3} - 1=0\\

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\frac{x - 5y}{y^3} - 1=0

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2 years ago
Andrew is two years older than Beatrice, and Chris is three years younger than Beatrice. The product of Andrew's age and Chris'
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Answer:

9

Step-by-step explanation:

A = B + 2

C = B - 3

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5 0
2 years ago
MARSVECTORCALC6 3.4.020. My Notes A rectangular box with no top is to have a surface area of 64 m2. Find the dimensions (in m) t
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Answer:

We would have

                                    l =w =\frac{8\sqrt{3}}{3} \\h = \frac{8\sqrt{3}}{6}

where " l " is  length, " w"  is width and "h" is height.

Step-by-step explanation:

Step 1

Remember that

         Surface area for a box with no top = lw+2lh+2wh = 64

where " l " is  length, " w"  is width and "h" is height.

 Step 2.

Remember as well that

                              Volume of the box = l*w*h

Step 3

 We can now use lagrange multipliers.  Lets say,

                                    F(l,w,h) = lwh

and

                                g(l,w,h) = lw+2lh+2wh = 64

By the lagrange multipliers method we know that                            

 

                                                     \nabla F  = \lambda \nabla g

Step 4

Remember that

                          \nabla F  = (wh,lh,lw)

and

                      \nabla g = (w+2h,l+2h , 2w+2l)

So basically you will have the system of equations

                              wh = \lambda (w+2h)\\lh = \lambda (l+2h)\\lw = \lambda (2w+2l)

Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get

                                   lwh = l\lambda (w+2h)\\\\lwh = w\lambda (l+2h)\\\\lwh = h\lambda (2w+2l)

Then you would get

                      l\lambda (w+2h) = w\lambda (l+2h) =  h\lambda (2w+2l)

You can get rid of \lambda from these equations and you would get

                         lw+2lh = lw+2wh =  2wh+2lh

And from those equations you would get

                                             l = w =2h

Now remember the original equation

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If we plug in what we just got, we would have

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3 years ago
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The probability of he/she is a technician or production operator will be 7/8.

<h3>What is probability?</h3>

The probability of an event occurring is defined by probability.

If you flip a coin, the likelihood that it will land on its head or tail is nothing more than the chance that either the head or the tail will occur.

Given,

Event 1 = selection of technician

Event 2 = selection of production operator

Since both events are independent and nothing has common in between

So,

P(1 or 2 ) = p(1) × p(2)

So,

probability (technician or production operator) = probability of technician × probability of production operator.

Probability (technician or production operator) = 10/40 + 25/40 = 7/8

Hence the probability of he/she is a technician or production operator will be 7/8.

For more information about the probability

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