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ASHA 777 [7]
2 years ago
14

2(x-1) ≥ 10 or 3-4x > 15 Solve the compound inequality, and show work!

Mathematics
2 answers:
Veseljchak [2.6K]2 years ago
5 0

Answer:

x\geq 6\text{ or } x

Step-by-step explanation:

We have the compound inequality:

2(x-1)\geq10\text{ or } 3-4x>15

Let's solve each of them individually first:

We have:

2(x-1)\geq10

Divide both sides by 2:

x-1\geq5

Add 1 to both sides:

x\geq6

We have:

3-4x>15

Subtract from both sides:

-4x>12

Divide both sides by -4:  

x

Hence, our solution set is:

x\geq 6\text{ or } x

Nimfa-mama [501]2 years ago
3 0

Answer:

x ≥ 6 or x < -3

Step-by-step explanation:

2(x-1) ≥ 10 or 3 - 4x > 15

2x - 2 ≥ 10 4x < -12

x ≥ 6 or x < -3

Topic: Inequalities

If you would like to venture further into mathematics, you can check out my Instagram page (learntionary) where I post notes and mathematics tips. Thanks!

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Answer:

\sum^\infty_{n=0} -5 (\frac{x+2}{2})^n

Step-by-step explanation:

Rn(x) →0

f(x) = 10/x

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Taylor series for the function <em>f </em>at the number a is:

f(x) =  \sum^\infty_{n=0} \frac{f^{(n)}(a)}{n!} (x - a)^n

f(x) = f(a) + \frac{f'(a)}{1!}(x-a)+\frac{f"(a)}{2!} (x-a)^2 + ... ............ equation (1)

Now we will find the function <em>f </em> and all derivatives of the function <em>f</em> at a = -2

f(x) = 10/x            f(-2) = 10/-2

f'(x) = -10/x²         f'(-2) = -10/(-2)²

f"(x) = -10.2/x³      f"(-2) = -10.2/(-2)³

f"'(x) = -10.2.3/x⁴     f'"(-2) = -10.2.3/(-2)⁴

f""(x) = -10.2.3.4/x⁵    f""(-2) = -10.2.3.4/(-2)⁵

∴ The Taylor series for the function <em>f</em> at a = -4 means that we substitute the value of each function into equation (1)

So, we get \sum^\infty_{n=0} - \frac{10(x+2)^n}{2^{n+1}} Or \sum^\infty_{n=0} -5 (\frac{x+2}{2})^n

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8 0
2 years ago
Read 2 more answers
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