3 years ago

(5x^2 - 2x^3 + x) - (6x^3 - 8x^2 - x)

Mathematics

2 answers:

pashok25 [27]3 years ago

8 0

Answer:

-8x^3+13x^2+2x

Sophie [7]3 years ago

7 0

Correct answer:

-8x^3 + 13x^2 + 2x

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What are the solutions to the quadratic equation x^2-16=0

maks197457 [2]

Good evening.

This is a incomplete quadratic equation, because it does not have the term bx. Therefore, we can solve this faster with the following strategy:

$\mathsf{x^2 - 16 = 0}$

Add 16 to both sides:

$\mathsf{x^2 - 16 + 16 = 0 + 16}\\ \\ \mathsf{x^2 = 16}$

Take the square root:

$\mathsf{\sqrt {x^2} = \pm\sqrt{16}}\\ \\ \mathsf{\boxed{\mathsf{x = \pm4} }}$

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$\boxed{\boxed{\mathsf{S=\{-4, \ +4\}}}}$

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12 – 2x= -2(y – x)<br> -2x = -2(y – x) – 12<br> x= (y - x) + 6

Vilka [71]

Answer:

x=o and y= -6

Step-by-step explanation:

12-2x = - 2(y-x)

or,12-2x = -2y + 2x

or, 12 = - 2y + 4x

or, 12/2= 2x - y

or, 2x - y = 6

• 2x -6= y.....eqn_1

-2x=-2y+2x -12

or,4x +2y= -12

or,4x + 2(2x-6)= -12

or, 4x+4x-12=-12

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• x= o

putting the value of x in eqn...3

o=(y-0)+6

or, o= y + 6

•y = -6

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