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Yuki888 [10]
2 years ago
7

Can anyone factor this?? I'm a little lost tysm!!!! 5x^2+12x+4 5x 2 +12x+4

Mathematics
1 answer:
Sergio039 [100]2 years ago
6 0

For a polynomial of the form ax^2+bx+c rewrite the middle term as a sum of two terms whose product is a⋅c=5⋅4=20 and whose sum is b=12.

<u>Factor 12 out of 12x.</u>

5x^2+12(x)+4

<u>Rewrite 12 as 2 plus 10</u>

5x^2+(2+10)x+4

Apply the distributive property.

5x^2+2x+10x+4

Factor out the greatest common factor from each group.

Group the first two terms and the last two terms.

(5x^2+2x)+10x+4

Factor out the greatest common factor (GCF) from each group.

x(5x+2)+2(5x+2)

Factor the polynomial by factoring out the greatest common factor, 5x+25x+2.

(5x+2)(x+2)

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Brilliant_brown [7]

Answer:

The correct option is;

Jason's statement is correct. RST is the same orientation, shape, and size as ABC

Step-by-step explanation:

Here we have

ABC = (2, 1), (3, 3), (4, 1)

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Therefore the length of the sides are as follows

AB = \sqrt{(2-3)^2+(1-3)^2} = \sqrt{5}

AC = \sqrt{(2-4)^2+(1-1)^2} =2

BC = \sqrt{(3-4)^2+(3-1)^2} = \sqrt{5}

For triangle SRT we have

RS = \sqrt{(-4-(-3))^2+(-2-0)^2} = \sqrt{5}

RT = \sqrt{(-4-(-2))^2+(-2-(-2))^2} = 2

ST = \sqrt{(-3-(-2))^2+(0-(-2))^2} = \sqrt{5}

Therefore their dimensions are equal

However the side with length 2  occurs between (2, 1) and (4, 1) in triangle ABC and between (-4, -2) and (-2, -2) in triangle RST

That is Jason's statement is correct. RST is the same orientation, shape, and size as ABC.

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3 years ago
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Romashka-Z-Leto [24]

Answer:

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Step-by-step explanation:

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2 years ago
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Step-by-step explanation:

2 functions start by making a domain

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Answer:

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Step-by-step explanation:

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