Which equation has a slope of 3?

2 answers:

6 0

Answer: The correct answer is C.

Explanation: The slope can be found in the equation y=mx+b. The number in place of the m is the slope of the equation.

Example: y=5x+2
The slope of this equation would be 5.

monitta2 years ago

5 0

Answer:

the correct answer is C

Step-by-step explanation:

mx+b

You might be interested in

Each car in a rental fleet is either red or white, and there are 75 cars total. There are three more white than twice the number

professor190 [17]

Number of red cars = x
Number of white cars = y

x + y = 75
y + 3 = 2x

x + y = 75
y = 75 - x

(75 - x) + 3 = 2x
78 = 3x
26 = x

y + 3 = 2(26)
y + 3 = 52
y = 49

There are 49 white cars.

8 0

3 years ago

Read 2 more answers

Ella has only quarters and nickels in her wallet. She has 2 more quarters than nickels. The total value of the coins is $2.00

aleksley [76]

Ella has 5 nickles and 7 quarters

8 0

3 years ago

Read 2 more answers

Please help me figure this work sheet out

soldi70 [24.7K]

I’ve attached my work!
Hope it helps :)
If you have any questions or anymore help lmk, happy to help with any school work!!
Have a nice day

4 0

3 years ago

Use the distributive property to simplify this expression<br> -9(n-4)

nirvana33 [79]

Answer:

-9n + 36

Step-by-step explanation:

1. -9(n - 4) -Distribute

2. -9n + 36 -Answer

7 0

3 years ago

I need help solving x^2+3xy-y^2=12 and x^2-y^2=-12

Georgia [21]

$substitute:x^2-y^2=-12\ to\ x^2+3xy-y^2=12\\\\3xy-12=12\\3xy=12+12\\3xy=24\ \ \ \ \ /:3\\xy=8\to x=\frac{8}{y}\\\\substitute\ to\ x^2-y^2=-12\\\\\left(\frac{8}{y}\right)^2-y^2=-12\\\\\frac{64}{y^2}=y^2-12$

$\frac{64}{y^2}=\frac{y^2-12}{1}\\\\y^2(y^2-12)=64\\\\y^4-12y^2-64=0\\\\substitute:y^2=t > 0\\\\t^2-12t-64=0$

$a=1;\ b=-12;\ c=-64\\\Delta=b^2-4ac\to\Delta=(-12)^2-4\cdot1\cdot(-64)=144+256=400\\\\t_1=\frac{-b-\sqrt\Delta}{2a};\ t_2=\frac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{400}=20\\\\t_1=\frac{12-20}{2\cdot1}=\frac{-8}{2}=-4 < 0;\ t_2=\frac{12+20}{2\cdot1}=\frac{32}{2}=16\\\\y^2=16\Rightarrow y=\pm\sqrt{16}\Rightarrow y=-4\ or\ y=4\\\\x=\frac{8}{-4}=-2\ or\ x=\frac{8}{4}=2\\\\Solution:x=-2\ and\ y=-4\ or\ x=2\ and\ y=4$

3 0

3 years ago