Answer:
True
Explanation:
In this case, the advancement payment can help with the payment of the money owned by the taxpayer over a definite period of time. This enables a step-wise payment of the monies that will be owed over a flexible time period, in this case, the period of 36 months that translates to the three-year period. In this period, the tax can be paid in small amounts with an increment in the interest as applicable.
Answer: low invol- Georgina Megan Dina
High invol Laura Charles jonny
Explanation:
Answer:
Mark should include in the letter to avoid litigation charges:
Specific facts about the consultant that can be verified.
Explanation:
False information, sentiment-hurting statements, or personal opinions about the consultant's character should never be found in formal letters that are meant to offer constructive criticisms. This means that only specific facts that are verifiable should be included. Formal letters are not avenues for character defamation. They are called "formal" because they must stick to specific and relevant official purposes.
Answer:
loss on fire and storms 710,000
insurance expense zero as the firm didn't acquire any
Explanation:
Notice it state <u><em>"if the company were to obtain insurance"</em></u> Which means it currently has none insurance.
If the firm had an insurance the amount of losses would be deducted from the insurance policy but there is none so we disclosure the entire loss as a result of the period.
Hence, we should recognize the entire loss on fire and storm damage of 710,000 during the year and no insurance expense.
Answer:
Explanation:
Annual demand (D) = 20000 units
Number of days per year = 250
Demand rate(d) = D/number of days per year = 20000/250 = 80 units
Production rate(p) = 655 units
Set up cost(S) = $1800
Holding cost (H) = $1.50
A) Optimum run size(Q) = sqrt of {2DS / H [1-(d/p)]}
= sqrt of {(2x20000x1800) /1.50[1-(80/655)]}
= Sqrt of [7200000/1.50(1-0.1221) ]
= sqrt of [72000000/(1.50 x 0.8779)]
= sqrt of (7200000/1.31685)
= Sqrt of 5467593.1199
= 2338 units
b) Maximum inventory ( I - max) = (Q/p) (p-d) = (2338/655)(655-80) = 3.5695 x 575 = 2052.46 or rounded off to 2052 units
Average inventory = I-max/2 = 2052/2 = 1026 units
C) Number of production setups per year = D/Q = 20000/2338 = 8.55 or rounded up to 6
d) optimal length of production run = optimal run size /production rate = 2338/655 = 3.56 or rounded up to 4 days
