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Romashka-Z-Leto [24]
3 years ago
11

Which of the following are the possible allele combinations from the gametes of an organism with the genotype of AaBb?

Biology
2 answers:
jasenka [17]3 years ago
7 0
AB ?? I think I’m
Not for sure
Lapatulllka [165]3 years ago
3 0

Answer:

AB I'm pretty sure ysv6igscugz hii shivhxhix vhzo xvjz joxpj xj

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A cross of blue x blue (both heterozygous) would result in
umka21 [38]

75% Blue

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If both are Heterozygous, that would mean that they're both Bb.

That would mean that it'll be Bb, Bb.

       B      b

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Explain how these tail lengths were inherited by describing the mode of inheritance, indicating how many gene pairs were at work
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Here we can see that 7 phenotypes appeared in F2 generation, so the number of genes involved is 3 and alleles is 6. Contribution per allele = 4 cm Base contribution = 6 cm

Genotype of Harvey = aa bb cc Genotype of Erma = AA BB CC

Number of dominant alleles if length is

18 cm = 18-6 / 4 = 12 / 4 = 3.

F1 generation genotype = Aa Bb Cc This clarifies why the length is 18 cm, as there are three dominant alleles.

seven 1. It is likely that there are gene pairs in this cross. There are

categories of phenotypes. The genotypes of the parents would be combinations of alleles that would produce a 6 cm ( aabbcc ) tail and a 30 cm) tail, whereas the 18 cm offspring would have a genotype of AaBbcc.

learn more about phenotypes here: brainly.com/question/902712

#SPJ4

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