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son4ous [18]
3 years ago
8

Casey transfers property with a tax basis of $2,000 and a fair market value of $5,000 to a corporation in exchange for stock wit

h a fair market value of $4,000 and $400 in a transaction that qualifies for deferral under section 351. The corporation assumed a liability of $600 on the property transferred. Casey also incurred selling expenses of $300. What is the amount realized by Casey in the exchange?
A. $5,000
B. $4, 700
C.. $4, 600
D. $4, 200
Business
1 answer:
pochemuha3 years ago
7 0

Answer:

B. $4,700

Explanation:

Calculation for the amount realized by Casey in the exchange

Using this formula

Amount realized in the exchange=Fair market value+ Qualifies deferral transaction+Property transferred Liability-Incurred selling expenses

Let plug in the formula

Amount realized in the exchange=$4,000 +$400 +$600 - $300

Amount realized in the exchange=$4,700

Therefore the amount realized by Casey in the exchange will be $4,700

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g Last year Thomson Inc's earnings per share (EPS) were $3.50, and its growth rate during the prior 5 years was 6.6% per year. I
mariarad [96]

Answer:

17.19   years

Explanation:

The triple value of the earnings per share=$3.50*3=$10.50

The growth rate is 6.6%

Using the nper formula in excel, we can determine the number of years earnings per share would triple

=nper(rate,pmt,-pv,fv)

rate is 6.6%

pmt is not applicable to the scenario ,hence it is zero

pv is the current earnings per share

fv is the future earnings per share

=nper(6.6%,0,-3.5,10.5)= 17.19  

8 0
3 years ago
4. How much higher or lower will net operating income be if the underapplied or overapplied overhead is allocated to Work in Pro
NISA [10]

Answer:

Net operating income will be $ 19630 ( greater ¢ ) if the ( underapplied ¢ J overhead is allocated among work in process, finished goods, and cost of goods sold rather than closed directly to cost of goods sold.

Explanation:

(Round your intermediate calculations and percentage values to 2 decimal places and final answers to the nearest dollar amount. Input the amount as positive value. Omit the "$" sign in your response.)

4 0
3 years ago
Which file should you edit to limit the amount of concurrent logins for a specific user? (tip: enter the full path to the file.
saul85 [17]

Use /etc/security/limits.conf file to limit amount of concurrent logins for a specific user.

Use the /etc/security/limits.conf record to restrict aid use for all packages. That is from the pam_limits module of the Plugable Authentication Modules (PAM) module set. Entries in /etc/security/limits.conf comprise the subsequent: Entity type limit value.

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3 0
1 year ago
Suppose that a planet fitness studio has fixed expenses of $7500 per month and variable expenses of $4.99 per member per month.
natka813 [3]
Answer: $500

$19.99-$4.99=$15
$7500/$15= $500
6 0
3 years ago
The owner of an orange grove must decide when to pick one variety of oranges. She can sell them for $27 a bushel if she sells th
uysha [10]

Answer:

The oranges should be picked in 2 weeks for maximum return

Explanation:

We assume that the return of the owner is y ($)

Assume that the number of weeks the oranges should be picked to have maximum return is x (weeks). (x≥0)

If collect now, the price for each bushel is $27

As the price per bushel decrease by $1.50 per bushel each week

=> After x weeks, the price of a bushel decrease: 1.5x ($)

=> The price of 1 bushel after x weeks is: 27 - 1.5x ($)

If collect now, each tree can yield 7 bushels

As the yield increases by half a bushel per week for the next 5 weeks

=> After x weeks with x ≤ 5, each trees would yields: 7 + 0.5x (bushels)

The return = The price of each bushes × The quantity of bushels

=> y = (27-1.5x)(7+0.5x)

⇔y= 27 (7 +0.5x) - 1.5x(7+0.5x) = 189 + 13.5x - 10.5x - 0.75x^{2}

⇔y = -0.75x^{2} +3x +189

We have: if the equation has the form of y =ax^{2} +bx +c with a≠0, its maximum value is: max y = c - \frac{b^{2} }{4a}

In the equation y = -0.75x^{2} +3x +189, we have: a = -0.75; b = 3; c = 189

=> max y = c -\frac{b^{2} }{4a} = 189 - \frac{3^{2} }{4.(-0.75)} = 189 - \frac{9}{-3}  = 189 - (-3) = 189+3 = 192

To look for the number of weeks, we should find x (0≤x≤5) with which y = 192

192 = -0.75x^{2} +3x +189

⇔-0.75x^{2} + 3x + 189 - 192 = 0

⇔-0.75 x^{2} + 3x - 3 =0

⇔-0.75x^{2}  + 4*0.75x - 0.75*4 =0

⇔x^{2} -4x + 4 = 0

⇔ (x-2)^{2}  = 0

⇔ x = 2

The oranges should be picked in 2 weeks for maximum return

7 0
3 years ago
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