Answer:
In order to find out the genotype we do a testcross of green pea pods with yellow pea pods.
Explanation:
1. If the F1 generation consist of green pea pods only then the genotype of the green pea pod is 'GG' (i.e the dominant alleles).
<h2>
TEST CROSS
</h2>
Green pea pods X Yellow pea pods
GG X gg
<u>Gametes:
</u>
G X g
<u> F1 Generation:
</u>
<h2>
Gg
</h2>
2. However if the F1 generation consist of 50% green pea pods and 50% yellow pea pods then the genotype of green pea pods is 'Gg' (both the dominant and recessive alleles).
Green pea pods X Yellow pea pods
Gg X gg
<u>Gametes:
</u>
G g X g
<u>F1 Generation:</u>
<h2> Gg, gg
</h2>
We can relate this to Mendel's Law of segregation and meiosis as
- Both the alleles segregate into seperate gametes (i.e they are sorted independent of one another).
- This segregation is similar to the first division of meiosis in which homologous chromosomes of gene are segregated in daughter nuclei
Answer:
B) 300
Explanation:
There are two types of alleles present for wing type in this population of Drosophila, c and c+. Various combinations of these two alleles will produce different phenotypes.
c+c+ : straight wings = 45
c+c: straight wings = 70
cc: curly wings = 35
Total flies = 150
Each fly has one gene with two alleles for wing type. Hence 150 flies will have 300 alleles in the gene pool.
The answer is A- sperm and egg. gametes are reproductive cells in mammals, so sperm and egg would be the correct.
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