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Aloiza [94]
3 years ago
8

Find the lateral surface 14ft area of the 2ft cylinder. Round your answer to the nearest tenth if necessary.

Mathematics
1 answer:
tatyana61 [14]3 years ago
3 0

Answer:

616 square feet

Step-by-step explanation:

Lateral surface area of a cylinder can be determined by;

Lateral surface area = 2\pirh

where: r is its radius, and h is its height.

Given in the question that the height of the cylinder is 14 feet and of radius 2 feet, then;

Lateral surface area = 2\pirh

                         = 2 x \frac{22}{7} x 2 x 14

                         = 2 x 22 x 2 x 7

                         = 616

Lateral surface area = 616 square feet

Thus, the lateral surface area of the cylinder is 616 square feet.

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Determine the following:
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Answer:

a) P(X = 0) = 0.5997

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c) P(X = 8) = 0.0047

d) P(X = 5) = 0.4018

Step-by-step explanation:

These following problem are examples of the binomial probability distribution.

Binomial probability

Th binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

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P(X = 0) = C_{4,0}.(0.12)^{0}.(0.88)^{4} = 0.5997

(b) for n = 10 and π = 0.40, what is P(X = 9)?

P(X = 9) = C_{10,9}.(0.4)^{9}.(0.6)^{1} = 0.0016

(c) for n = 10 and π = 0.50, what is P(X = 8)?

P(X = 8) = C_{10,8}.(0.5)^{8}.(0.5)^{2} = 0.0047

(d) for n = 6 and π = 0.83, what is P(X = 5)?

P(X = 5) = C_{6,5}.(0.83)^{5}.(0.17)^{1} = 0.4018

3 0
3 years ago
Find the slope of the line that passes through
Andreyy89

Answer:

-1/3

Step-by-step explanation:

Use rise over run (y2 - y1) / (x2 - x1)

Plug in the 2 points:

(y2 - y1) / (x2 - x1)

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Step-by-step explanation:

The solution to this problem requires that we find other units besides the given one

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3.m/s

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2. converting to km/h

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3. converting to m/s

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