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xenn [34]
3 years ago
6

F(x) = x + 7, g(x) = x - 7 (a) (f + g)(x) = (b) (f-g)(x)= (c) (fg)(x)= (d) (f/g)(x)=

Mathematics
1 answer:
Vlada [557]3 years ago
7 0

a) 2x

b) 14

c) x^2 -49

d) -1

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On a map, 3 centimeters represents 150 kilometers. If a line between two cities measures 4.5 centimeters, how many kilometers ap
SCORPION-xisa [38]

Answer: 225km

Step-by-step explanation:

3cm --- 150

1cm ---- 50

Therefore 4.5cm * 50 = 225km

7 0
2 years ago
Find the equation of the line that is perpendicular to the line x = −5 and passes through the point (1, π).
Tanzania [10]

The line x = -5 is a vertical line, therefore the line perpendicular to this line is the horizontal line of the form y = a.

We know that it passes through the point (1, π) → x = 1, y = π.

Therefore we have answer: A) y = π.

5 0
3 years ago
Plz help i realy need it im gonna fail if i dont get this
Anna11 [10]

Answer:

It is between 13 and 13.5

Step-by-step explanation:

Well 13^2 = 169 and 13.5^2 = 182.25

It is between 13 and 13.5

3 0
3 years ago
Each of these extreme value problems has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to f
tino4ka555 [31]

Answer:

The minimum value of the given function is f(0) = 0

Step-by-step explanation:

Explanation:-

Extreme value :-  f(a, b) is said to be an extreme value of given function 'f' , if it is a maximum or minimum value.

i) the necessary and sufficient condition for f(x)  to have a maximum or minimum at given point.

ii)  find first derivative f^{l} (x) and equating zero

iii) solve and find 'x' values

iv) Find second derivative f^{ll}(x) >0 then find the minimum value at x=a

v) Find second derivative f^{ll}(x) then find the maximum value at x=a

Problem:-

Given function is f(x) = log ( x^2 +1)

<u>step1:</u>- find first derivative f^{l} (x) and equating zero

  f^{l}(x) = \frac{1}{x^2+1} \frac{d}{dx}(x^2+1)

f^{l}(x) = \frac{1}{x^2+1} (2x)  ……………(1)

f^{l}(x) = \frac{1}{x^2+1} (2x)=0

the point is x=0

<u>step2:-</u>

Again differentiating with respective to 'x', we get

f^{ll}(x)=\frac{x^2+1(2)-2x(2x)}{(x^2+1)^2}

on simplification , we get

f^{ll}(x) = \frac{-2x^2+2}{(x^2+1)^2}

put x= 0 we get f^{ll}(0) = \frac{2}{(1)^2}   > 0

f^{ll}(x) >0 then find the minimum value at x=0

<u>Final answer</u>:-

The minimum value of the given function is f(0) = 0

5 0
3 years ago
What is the simplified form of the expression of the square root of 121/81
larisa [96]
Decimal form : 2.61728395
Mixed Number: 2  50/81
3 0
3 years ago
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