Ask question

Ask question

All categories

2 years ago

7

A movie rental service is $5 a month after a one time start up fee of $60. Wrote an equation in slope-intercept form modeling th

is situation.identify the independent(x) and dependent (y) variables. After one year,how much would you have spent at the rental service?

1 answer:

alisha [4.7K]2 years ago

6 0

Answer:

y=60+5x and you would have spent $120

Step-by-step explanation:

You might be interested in

HELP DISTRIBUTIVE PROPERTY QUADRATICS PLZZZZZZZ

Vlad1618 [11]

1: x² + 10x + 25
2: x² - x -12
3: -2x² + 10x
4: -2x² + 9x + 5
5: n² - 4
---------------------------
1: x² + 14x + 49
2: x² - 14x + 49
3: 4n² - 20n + 25
4: 4n² + 20n +25
5: you just have to switch the signs

4 0

3 years ago

Harper brought $45 to the bowling alley. She spent $25 on bowling and plans to spend the rest of the money playing arcade games.

sammy [17]

Answer:

45-25=20 If you do 20 divided by 0.25 you will get your answer.

3 0

2 years ago

A border is made of 33 2/3 bricks that are 1 1/6 feet long. About how long is the boder.

stepan [7]

39.277 is how long the border is

3 0

3 years ago

Brandon and carlos played a game of darts, and carlos scored 30 more points than brandon. The total of their score was 142 point

Temka [501]

Answer:

Brandon scored 56 points and Carlos scored 86 points.

Step-by-step explanation:

142-30=112

112/2=56

56+30=86

3 0

2 years ago

Photos and videos have become an important part of the online social experience, with more than half of Internet users posting p

klasskru [66]

Answer:

0.82

Step-by-step explanation:

Given:

<em>A</em> be the event that an Internet user posts photos taken by themselves.

<em>B</em> be the event that an Internet user posts photos taken by themselves.

P(A) = 0.47

P(A) = 0.28

P(A or B) = $P(A\cup B)$ = 0.52

To find:

Conditional probability that an Internet user posts photos given that they post videos.

OR

P(A/B) = ?

Solution:

<em>Formula </em>to be used to find the required conditional probability:

$P(A/B) = \dfrac{P(A \cap B)}{P(B)}$

For this, $P(A \cap B)$ is required.

<em>Formula</em>

$P(A \cup B) = P(A) + P(B) - P(A \cap B)$

$0.52=0.47+0.28-P(A\cap B)\\\Rightarrow P(A\cap B)=0.23$

Now, the required conditional probability is:

$P(A/B) = \dfrac{P(A \cap B)}{P(B)}\\\Rightarrow P(A/B) = \dfrac{0.23}{0.28}\\\Rightarrow \bold{P(A/B)} = 0.82}$

So, the answer is <em>0.82</em>.

5 0

3 years ago