Answer: First option is correct.
Step-by-step explanation:
Since we have given that
![6x^3+6](https://tex.z-dn.net/?f=6x%5E3%2B6)
Now, by factorising , we get
![6x^3+6\\=6(x^3+1)](https://tex.z-dn.net/?f=6x%5E3%2B6%5C%5C%3D6%28x%5E3%2B1%29)
Now, we use the formula i.e.
![a^3+b^3=(a+b)(a^2-ab+b^2)](https://tex.z-dn.net/?f=a%5E3%2Bb%5E3%3D%28a%2Bb%29%28a%5E2-ab%2Bb%5E2%29)
By using this, we get ,
![6(x^3+1)\\=6(x+1)(x^2-x+1)](https://tex.z-dn.net/?f=6%28x%5E3%2B1%29%5C%5C%3D6%28x%2B1%29%28x%5E2-x%2B1%29)
So,
![(x+1) \text{ is the factor of }6x^3+6.](https://tex.z-dn.net/?f=%28x%2B1%29%20%5Ctext%7B%20is%20the%20factor%20of%20%7D6x%5E3%2B6.)
Answer = 1/32768
Therefore A Is the correct option
Pretty sure it’s -2 i’m sorry if it’s wrong tho
Answer
I think it’s d
Explanation
Answer:
D
Step-by-step explanation:
Count the number of places it takes to get one place past 3
There are 5 zeros in the given question. That gets you to just before the 3.
Add one more to get past the 3. That makes 5 zeros + 1 more place = 6
Since you are moving right, the 6 is minus. Your answer is 3 * 10^-6