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QveST [7]
4 years ago
5

Two main ways in which organisms interact are?

Chemistry
1 answer:
Mashcka [7]4 years ago
6 0
Competition and predations.  
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Select the appropriate statements and arrange them in a logical order to explain the bonding in BeF2. i. Each of the singly occu
galina1969 [7]

Answer:

e.iv, iii, i, ii

Explanation:

Be has electron configuration of 1s^2 2s^2. During bond formation, one 2s electron is promoted to a 2p orbital. Hence two hybrid sp beryllium orbitals are formed. These two hybrid orbitals are used in sigma bond formation to fluorine atoms.

Recall that fluorine has filled 2p orbitals containing lone pairs of electrons. These filled orbitals can interact with the unhybridized 2p-orbitals on beryllium to form pi bonds. This is the reason for the sequence of events chosen in the answer.

4 0
4 years ago
What is formed in the neutralization reaction between a strong acid and a strong base? (2 points)
Alborosie

A neutralization reaction is when an acid and a base react to form water and a salt and involves the combination of H+ ions and OH- ions to generate water. The neutralization of a strong acid and strong base has a pH equal to 7.

5 0
3 years ago
Read 2 more answers
What is the difference between an endothermic reaction and an endothermic process?​
Gnoma [55]

Answer:

An exothermic process releases heat, causing the temperature of the immediate surroundings to rise. An endothermic process absorbs heat and cools the surroundings

3 0
3 years ago
Chemical Quantities "Molar Mass - 2 step" - Wksh #3 Directions: Use dimensional analysis to perform the following calculations.
fomenos

There are about 1.27  × 10^23 molecules present in 13.5 g of SO2.

<h3>What are molecules?</h3>

A molecule is the simplest part of a compound that have independent existence.

Number of moles of sulfur dioxide = 13.5 g/64 g/mol = 0.211 moles

If 1 mole of SO2 contains 6.02 × 10^23 molecules

0.211 moles of SO2 contains 0.211 moles × 6.02 × 10^23 molecules/1 mole

= 1.27  × 10^23 molecules

32 g of sulfur contains 6.02 × 10^23 atoms

x g of sulfur contains  2.23 x 10^23

x = 32 × 2.23 x 10^23 /6.02 × 10^23

x = 11.85 g

6.02 × 10^23 formula units has a mass of AgF = 127 g

x formula units has a mass of  = 42.15 g

x = 6.02 × 10^23 × 42.15/127

x = 2 × 10^23 formula units

6.02 × 10^23 formula units of Fe2O3 has a mass of 160 g

8.83 x 10^23 formula units of Fe2O3 has a mass of 8.83 x 10^23 x 160 g/6.02 × 10^23

x = 235 g

Learn more about formula unit: brainly.com/question/19293051

6 0
2 years ago
in a reaction 2.5g of sodium sulphate reacted with 4.5g of barium chloride. the products are 3.5g of barium sulphate and the res
klio [65]

The mass of sodium chloride : 3.5 g

<h3>Further explanation</h3>

Given

Reaction :

2.5g of sodium sulphate + 4.5g of barium chloride ⇒ 3.5g of barium sulphate + sodium chloride

Required

The mass of sodium chloride

Solution

Conservation of mass applies to a closed system, <em>where the masses before and after the reaction are the same</em>

From the reaction :

mass of reactants = 2.5 g + 4.5 g = 7.0 g

mass of products = 3.5 g + mass of sodium chloride

mass of reactants = mass of products

7.0 g = 3.5 g + mass of sodium chloride

mass of sodium chloride = 7 g - 3.5 g =3.5 g

3 0
3 years ago
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