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yulyashka [42]
3 years ago
10

Alice is buying a house with 625K. She is making 20% deposit. And get a mortgage on the balance.A bank offers her two options.

Mathematics
1 answer:
dem82 [27]3 years ago
4 0

Answer:

By opting for the second option, Alice would save $ 15,740.00  in total mortgage cost

Step-by-step explanation:

In order to determine the better of the two options available, we need to determine the total cost under each option as follows:

Option 1:

cost of house=$625,000

loan amount=$625,000-(20%*$625,000)=$500,000

loan amount=monthly payment*(1-(1+r)^-n/r

monthly payment is the unknown

r=monthly interest rate=4%/12=0.33333333%

n=number of monthly payments in 30 years=30*12=360

500,000=monthly payment*(1-(1+0.33333333% )^-360/0.33333333%

500,000=monthly payment*(1-0.301795869 )/0.003333333

500,000=monthly payment*0.698204131 /0.003333333

monthly payment=500,000*0.003333333 /0.698204131

monthly payment=$ 2,387.08  

total monthly payments=$ 2,387.08*360=$859,348.80

Option 2:

upfront fee=$10,000

loan amount=monthly payment*(1-(1+r)^-n/r

monthly payment is the unknown

r=monthly interest rate=3.75%/12=0.3125%

n=number of monthly payments in 30 years=30*12=360

500,000=monthly payment*(1-(1+0.3125%  )^-360/0.3125%

500,000=monthly payment*(1-0.325222459  )/0.003125

500,000=monthly payment*0.674777541  /0.003125  

monthly payment=500,000*0.003125  /0.674777541=$2,315.58  

Total cost=total monthly payments+upfromt fee

total cost=($2,315.58 *360)+$10,000=$843,608.80  

savings by opting for the second option=$859,348.80-$843,608.80  

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Step-by-step explanation:

Information given

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X=81 represent the number of people with type A blood

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p_o=0.4 is the value that we want to verify

\alpha=0.01 represent the significance level

z would represent the statistic

p_v{/tex} represent the p value Hypothesis to testWe want to test if the percentage of the population having type A blood is different from 40%.:  Null hypothesis:[tex]p=0.4  

Alternative hypothesis:p \neq 0.4  

the statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the info given we got:

z=\frac{0.5625 -0.4}{\sqrt{\frac{0.4(1-0.4)}{144}}}=3.98  

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p_v =2*P(z>3.98)=0.0000689  

Since the p value is very low compared to the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true percent of people with type A of blood is significantly different from 0.4 or 40%

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