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Ira Lisetskai [31]
3 years ago
11

Please Help!!!!! I will give points! Also can you show the work please!! :D

Mathematics
1 answer:
IgorC [24]3 years ago
4 0

Answer:

x = 132

Step-by-step explanation:

Angle S = 48   Angle T = 90   Angle W =

180 - 48 = 132

132 - 90 = 42

Angle W = 42

180 - 42 = 132

x = 132

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In a casino on a Saturday, 90% of the visitors lost $100 each, 9% of the visitors lost $1,000 each, and the rest won $10,000 eac
liq [111]

x = total amount of visitors


so we have 90% that lost $100, 9% that lost $1000, now 90+9 = 99%, what's left is just 1% then, so 1% won $10,000.

Profit is Revenue - Cost.

so the profit for the casino, is not who wins, because from the wins the casino needs to pay that to the winner, so they're losing that much, so for the casino, profits is when a player loses, so their profit will come from the 99% that lost money then.

keeping in mind that

\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em} \begin{array}{llll} \stackrel{\textit{90\% of x}}{\left( \cfrac{90}{100} \right)x}\implies 0.9x\qquad \stackrel{\textit{9\% of x}}{\left( \cfrac{9}{100} \right)x}\implies 0.09x \\\\\\ \stackrel{\textit{1\% of x}}{\left( \cfrac{1}{100} \right)x}\implies 0.01x \end{array}


since we know that 90% lost $100, that means 0.9x(100) is the total amount lost by all of them, since we also know that 9% lost $1000, then 0.09x(1000) is the total amount lost by them, and the wins are of course just 0.01x(100000).


\bf \stackrel{\textit{90\% at \$100}}{0.9x(100)}~~+~~\stackrel{\textit{9\% at \$1000}}{0.09x(1000)}~~-~~\stackrel{\textit{1\% at \$10000}}{0.01x(10000)}~~=~~\stackrel{\textit{casino's profit}}{80000} \\\\\\ 90x+90x-100x=80000\implies 80x=80000\\\\\\ x=\cfrac{80000}{80}\implies x=1000

4 0
4 years ago
Help me ASAP please
Umnica [9.8K]

Answer:

<h2>y ≤ 9</h2>

Step-by-step explanation:

\dfrac{1}{3}y+1\leq4\qquad\text{subtract 1 from both sides}\\\\\dfrac{1}{3}y\leq3\qquad\text{multiply both sides by 3}\\\\3\!\!\!\!\diagup^1\cdot\dfrac{1}{3\!\!\!\!\diagup_1}y\leq(3)(3)\\\\y\leq9

3 0
3 years ago
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