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Advocard [28]
3 years ago
7

35 divided by 1 3/4 and 5

Mathematics
1 answer:
larisa86 [58]3 years ago
8 0

Answer:

25

Step-by-step explanation:

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Dr. Johnson treated 1134 patients in 63 days.
Alchen [17]

Answer:

D= 18

Step-by-step explanation:

She treated 18 people on the average because 1134 dived by 63 is exactly 18.

:) :)

8 0
3 years ago
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Gina wants to take dance classes. She compares two dance studios to determine which has the best deal for her. Dance World charg
allsm [11]
The best answer for the this question is 15
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3 years ago
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How many solutions does this linear system of equations have?<br> x – 3y = 5<br> -3x + 9y = -7
Angelina_Jolie [31]

9514 1404 393

Answer:

  zero

Step-by-step explanation:

Dividing the second equation by -3, it becomes ...

  x -3y = 7/3

Compared to the first equation, ...

  x -3y = 5

we see that it is <em>inconsistent</em>. No values of the variables can satisfy both equations. There are no solutions.

6 0
2 years ago
A recent study from the University of Virginia looked at the effectiveness of an online sleep therapy program in treating insomn
Ludmilka [50]

Answer:

1. The 99% confidence interval for the difference in average is -6.47377 < μ₁ - μ₂ < -11.34623

2. The possible issues in the calculations includes;

a. The confidence level used in the confidence interval can influence the result of the confidence interval observed

b. The sample size is small

Step-by-step explanation:

1. The number of adults with insomnia in the sample = 45

The number of adults that participated in the therapy, n₁ = 22

The number of candidates that served as control group, n₂ = 23

The average score for the for the 22 participants of the program, \overline x_1 = 6.59

The standard deviation for the 22 participants of the program, s₁ = 4.10

The average score for the for the 23 subjects in the control group, \overline x_2 = 15.50

The standard deviation for the 23 subjects in the control group, s₂ = 5.34

The confidence interval for unknown standard deviation, σ, is given by the following expression;

\left (\bar{x}_{1}- \bar{x}_{2}  \right )\pm t_{\alpha /2}\sqrt{\dfrac{s_{1}^{2}}{n_{1}}+\dfrac{s_{2}^{2}}{n_{2}}}

α = 1 - 0.99 = 0.01

α/2 = 0.005

The degrees of freedom, df = 22 - 1 = 21

t_{\alpha /2} = t_{0.005, \, 21} = 1.721

Therefore, we have;

\left (6.59- 15.5  \right )\pm1.721 \cdot \sqrt{\dfrac{4.10^{2}}{22}+\dfrac{5.34^{2}}{23}}

The 99% confidence interval for the difference in average is therefore given as follows;

-6.47377 < μ₁ - μ₂ < -11.34623

Therefore, there is considerable evidence that the participants in the survey  had lower average score than the subjects in the control group

2. The possible issues in the calculations are;

a. The confidence level used in the confidence interval can influence the result of the confidence interval observed

b. The sample size is small

5 0
2 years ago
I need solving this problem ?
bearhunter [10]
I believe it's 6/12, but simplified to the lowest form is 1/2
8 0
3 years ago
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