The answer to this problem is 12.5
Answer:
1.5 kg of pepper cheddar cheese and 4.5 kg of Pennsylvania jack was used in the mixture.
Step-by-step explanation:
Pepper Cheddar cheese = $15 per kilogram
Pennsylvania jack = $11 per kilogram
The cheese sampler includes a Pepper Cheddar cheese and a Pennsylvania jack that cost $15 per kilogram and $11 per kilogram respectively.
The mixture = 6 kg
Let
a = kg of the pepper cheddar cheese
b = kg of the Pennsylvania jack
a + b = 6............(i)
Rate
15a + 11b/6 = 12
15a + 11b = 72.............(ii)
Combine the equation
a + b = 6............(i)
15a + 11b = 72.............(ii)
a = 6 - b
15(6 - b) + 11b = 72
90 - 15b + 11b = 72
90 - 72 = 15b - 11b
18 = 4b
divide both sides by 4
b = 18/4
b = 4.5 kg
insert the value of b in equation (i)
a + b = 6............(i)
a = 6 - 4.5
a = 1.5 kg
1.5 kg of pepper cheddar cheese and 4.5 kg of Pennsylvania jack was used in the mixture.
Any number above 0 so even .000000000000000000000001 gl on your homework.
Answer:
105°
Step-by-step explanation:
105°
Answer:
See below
Step-by-step explanation:
<u>Given relationship:</u>
a) r = 3, d = 4
- t = d/r = 4/3 h = 1 h 20 min
b) d = 4 miles, rate = r
- t = 4/r, domain is r and must be greater than zero
c) d = 4 miles, time = t
- r = d/t = 4/t, domain is t and it must be greater than zero
d) t = 3 h, rate = r
- d = rt = 3r, domain is r and can be anything greater than zero
