The hardest part of this would be finding the length of that arc. Though, since it's a quarter circle, it makes our job a whole lot easier.
The circumference of a circle is 2πr, therefore, a quarter circumference of a circle would be (2<span>πr) / 4.
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Therefore, the length of that arc would be (2 * 3.14<span> * 8) / 4 = 12.56
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With this figure, we can just add up the rest of the perimeter.
12.56 + 8 (circle radius) + 10 + 10 (two rectangle heights) + 17 (rectangle length) + 9 (rectangle length minus radius, for the top-right part of the rectangle), giving us an answer of 66.56cm
532.71
.55
The first step is lining up the decimals.
Then you add like normal
The answer would be 524.26
Answer:
Adia collects 87 nickels.
Step-by-step explanation:
Each nickel is worth 5 cents.
435 / 5 = 87
To find the volume, we should find the area of the triangle, the multiply by the depth of the object.
Area of Triangle = 1/2 * base * height = 5.7cm * 7.6cm / 2 = 21.66cm^2
Multiplying this by the depth of the object and we find:
21.66cm^2 * 4.8cm = 103.968cm^3
which we can round (if needed) to 103.97cm^3
Answer:
Step-by-step explanation:
Given the function
y = (9x⁴ — 4x² + 6)⁴
We need to find the derivative of y with respect to x i.e. dy/dx.
So let u = 9x⁴—4x² + 6
Then y = u²,
Then, y is a function of u, y=f(u)
Also, u is a function of x, u = g(x)
In this case,
u = g(x) = 9x⁴—4x² + 6
So let differentiate this function y(x).
This is a function of a function
Then, we need to find u'(x)
u (x) = 9x⁴—4x² + 6
Then, u'(x) = 36x³ — 8x
Also we need to find y'(u)
Then, y = u²
y'(u) = 2u
Using function of a function formula
dy / dx = dy/du × du/dx
y'(x) = y'(u) × u'(x)
y'(x) = 2u × 36x³ — 8x
y'(x) = 2u(36x³ — 8x)
Since, u = 9x⁴—4x² + 6
Therefore,
y'(t) = 2(9x⁴—4x² + 6)(36x³ — 8x)
So,
dy/dx = 2(9x⁴—4x² + 6)(36x³ — 8x)
dy/dx = (18x⁴—8x² + 12)(36x³ — 8x)
