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2 years ago

Please help me you'll get brainliest

Mathematics

1 answer:

Gnom [1K]2 years ago

8 0

Answer:

Step-by-step explanation:

4.5 + 4.5 = 9

9/3 = 3

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What are the coordinates of D’ when the quadrilateral is reflected across the line y = x?

Butoxors [25]

Answer:

(1, 3)

Step-by-step explanation:

If quadrilateral ABCD is reflected across the line y = x, then the x- and y-coordinates get reversed. Since the coordinates of point D are (3, 1), then the coordinates of point D' are (1, 3).

8 0

2 years ago

Read 2 more answers

The volume of

BARSIC [14]

0.1

1*100 = 100
100/1000
=0.1

8 0

3 years ago

Read 2 more answers

Given the sequence 2, 5, 8, 11, 14, ..., which term is 59? (Hint: find n.)

____ [38]

N = 3 ( the next number is 3 plus the previous number
sequence formula = an = 3(n-1) +2

so for term the term that =59

59 = 3(n-1) +2

distribute:
59 = 3n -3+2

59 = 3n -1

60 = 3n
n = 60/3
n = 20

59 is the 20th term

8 0

3 years ago

What is the volume, in cubic inches, of a cone that has a radius of 8 inches and a height of 12 inches? Use 3.14 for π , and rou

Doss [256]

Answer:

803.84 in^3

Step-by-step explanation:

First of all we have to find the base area

base area = radius^2 x 3.14 = 8^2 x 3.14 = 64 x 3.14 = 200,96 in^2

the volume can be find with this formula:

V = (base area x height)/3

V = (200.96 x 12)/3 = 803.84 in^3

8 0

2 years ago

Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)

Mnenie [13.5K]

One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
$(x-h)^2+(y-k)^2=r^2$
the center is (h,k) and the radius is r

and the distance formula is
distance between $(x_1,y_1)$ and $(x_2,y_2)$ is
$D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle

so
$(x+2)^2+(y-3)^2=18$
$(x-(-2))^2+(y-3)^2=(\sqrt{18})^2$
$(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2$

the radius is $3\sqrt{2}$
center is (-2,3)

find distance between (8,4) and (-2,3)

$D=\sqrt{(8-(-2))^2+(4-3)^2}$
$D=\sqrt{(8+2)^2+(1)^2}$
$D=\sqrt{10^2+1}$
$D=\sqrt{100+1}$
$D=\sqrt{101}$

$r=3\sqrt{2}$ ≈4.2
$D=\sqrt{101}$ ≈10.04

do r<D

(8,4) is outside the circle

6 0

3 years ago