Answer:
33°
Step-by-step explanation:
We were given that:
1- The angles of a triangle add up to 180 degrees
2- The second angle is 15 degrees larger than the smallest angle
3- The third angle is 3 times as big as the smallest angle
So, first of all, let's call the smallest angle x.
the second angle will be (x + 15°) since it is 15 degrees greater than the smallest angle
and the third will be 3x, since it is 3 times bigger than the smallest angle.
With the information we have, we can form an equation!
180° = x + (x+ 15°) + 3x
180° = 5x + 15°
180° - 15° = 5x + 15° - 15°
165° = 5x
165°/5 = 5x/5
33° = x
therefore, the smallest angle measures 33° degrees, the second angle measures 48° and the third angle measures 99°.
99° + 33° + 48° = 180°
so it is safe to say this answer is correct!
Answer:
z=-3
Step-by-step explanation:
-5z+9=24 so, subtract 9 from both sides becuase of liked terms to get -5z=15, then divide both sides by -5 to get z = -3 hope it helps:)
Answer:
6/7 = 66/77
9/11 = 63/77
6/7 is greater than 9/11
Step-by-step explanation:
To give fractions a common denominator you must find the LCM(lowest common multiple) of this two denominators.
So, we have 7 and 11. You must find a multiple 7 and 11 share. This means that the number must be divisible by 7 and 11. The LCM for 7 and 11 is 77.
Now we make both the denominators 77.
Now look at the numerators. Look at 6/7. We multipled 7 by 11 to get 77. Therefore, we must also multiply 6 by 11.
Now we have, 66/77
Do the same with the other fraction but other way around:
11 x 7 so
9 x 7 = 63
So,
63/77
So 6/7 is now 66/77 and 9/11 is now 63/77
Now compare:
66 > 63
66 is bigger so 6/7 is greater.
6/7 is greater than 9/11
Answer: ![3x^2y\sqrt[3]{y}\\\\](https://tex.z-dn.net/?f=3x%5E2y%5Csqrt%5B3%5D%7By%7D%5C%5C%5C%5C)
Work Shown:
![\sqrt[3]{27x^{6}y^{4}}\\\\\sqrt[3]{3^3x^{3+3}y^{3+1}}\\\\\sqrt[3]{3^3x^{3}*x^{3}*y^{3}*y^{1}}\\\\\sqrt[3]{3^3x^{2*3}*y^{3}*y}\\\\\sqrt[3]{\left(3x^2y\right)^3*y}\\\\\sqrt[3]{\left(3x^2y\right)^3}*\sqrt[3]{y}\\\\3x^2y\sqrt[3]{y}\\\\](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27x%5E%7B6%7Dy%5E%7B4%7D%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B3%5E3x%5E%7B3%2B3%7Dy%5E%7B3%2B1%7D%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B3%5E3x%5E%7B3%7D%2Ax%5E%7B3%7D%2Ay%5E%7B3%7D%2Ay%5E%7B1%7D%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B3%5E3x%5E%7B2%2A3%7D%2Ay%5E%7B3%7D%2Ay%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B%5Cleft%283x%5E2y%5Cright%29%5E3%2Ay%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B%5Cleft%283x%5E2y%5Cright%29%5E3%7D%2A%5Csqrt%5B3%5D%7By%7D%5C%5C%5C%5C3x%5E2y%5Csqrt%5B3%5D%7By%7D%5C%5C%5C%5C)
Explanation:
As the steps above show, the goal is to factor the expression under the root in terms of pulling out cubed terms. That way when we apply the cube root to them, the exponents cancel. We cannot factor the y term completely, so we have a bit of leftovers.
