There's no diagram, so I made my own.
But I can't prove AD = 2*AB
Answer:
The quantity of water drain after x min is 50
Step-by-step explanation:
Given as :
Total capacity of rain barrel = 50 gallon
The rate of drain = 10 gallon per minutes
Let The quantity of water drain after x min = y
Now, according to question
The quantity of water drain after x min = Initial quantity of water × 
I.e The quantity of water drain after x min = 50 gallon × 
or, The quantity of water drain after x min = 50 gallon × 
Hence the quantity of water drain after x min is 50
Answer
G = F(4x+5)/ 3x-2
C = (4x+5) (3x-2)/ 24C
F = 3x-2/C
It is in simple form. There is absolutely nothing more that can be done, unless it is a joke. And math jokes are very hard to come by.
I don't think that y(y - 1)/(a + 2b) is any simpler.
Come to think of it, is that x^2 or y^2 on the top left.
I think my first answer is the best one. Nothing can be done.
Answer:
-3
Step-by-step explanation: