Question

11

Answer 1

Answer:

$A' = (0 ,1)$

$B' = (2,0)$

$C' = (0,-1)$

Step-by-step explanation:

Given

$A = (0,3)$

$B =(6,0)$

$C = (0,-3)$

$k =\frac{1}{3}$

Required

The new coordinates

The new coordinate is calculated as:

New = Old * Scale factor

So, we have:

$A' = A * k$

$A' = (0,3) * \frac{1}{3}$

Expand

$A' = (0 * \frac{1}{3},3 * \frac{1}{3})$

$A' = (0 ,1)$

$B' = B * k$

$B' = (6,0) * \frac{1}{3}$

$B' = (6 * \frac{1}{3},0 * \frac{1}{3})$

$B' = (2,0)$

$C' = C * k$

$C' = (0,-3) * \frac{1}{3}$

$C' = (0* \frac{1}{3},-3* \frac{1}{3})$

$C' = (0,-1)$