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2 years ago

Find the length of the line below. A. 2 in. B. 2 3/16 in. C. 2 5/16 in. D. 3 in.

Mathematics

1 answer:

Helen [10]2 years ago

3 0

Answer:

Step-by-step explanation:

Starting point is at o and ending point at 2.

So, 2 in

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If 1/8(8x+15)24, what is the value of x?

Lelechka [254]

Answer:

$x=22.125$ or $x=\frac{177}{8}$

Step-by-step explanation:

<u><em>The correct equation is</em></u>

$1/8(8x+15)=24$

solve for x

Multiply by 8 both sides to remove the fraction

$(8x+15)=192$

subtract 15 both sides

$8x=192-15\\8x=177$

divide by 8 both sides

$x=\frac{177}{8}$

$x=22.125$

3 0

3 years ago

Please could you find the answers to the questions in the attachment.

Fudgin [204]

( $\frac{x1+x2}{2} , \frac{y1+y2}{2}$ )we need 3 equations
1. midpoint equation which is ( $\frac{x1+x2}{2} , \frac{y1+y2}{2}$ ) when you have 2 points

2. distance formula which is D= $\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}$

3. area of trapezoid formula whhic is (b1+b2) times 1/2 times height

so

x is midpoint of B and C
B=11,10
c=19,6
x1=11
y1=10
x2=19
y2=6
midpoint=( $\frac{11+19}{2} , \frac{10+6}{2}$ )
midpoint=( $\frac{30}{2} , \frac{16}{2}$ )
midpoint= (15,8)

point x=(15,8)

y is midpoint of A and D
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
midpoint=( $\frac{5+21}{2} , \frac{8+0}{2}$ )
midpoint=( $\frac{26}{2} , \frac{8}{2}$ )
midpoint=(13,4)

Y=(13,4)

legnths of BC and XY
B=(11,10)
C=(19,6)
x1=11
y1=10
x2=19
y2=6
D= $\sqrt{(19-11)^{2}+(6-10)^{2}}$
D= $\sqrt{(8)^{2}+(-4)^{2}}$
D= $\sqrt{64+16}$
D= $\sqrt{80}$
D= $4 \sqrt{5}$
BC= $4 \sqrt{5}$

X=15,8
Y=(13,4)
x1=15
y1=8
x2=13
y2=4
D= $\sqrt{(13-15)^{2}+(4-8)^{2}}$
D= $\sqrt{(-2)^{2}+(-4)^{2}}$
D= $\sqrt{4+16}$
D= $\sqrt{20}$
D= $2 \sqrt{5}$
XY= $2 \sqrt{5}$

the thingummy is a trapezoid
we need to find AD and BC and XY
we already know that BC= $4 \sqrt{5}$ and XY= $2 \sqrt{5}$

AD distance
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
D= $\sqrt{(21-5)^{2}+(0-8)^{2}}$
D= $\sqrt{(16)^{2}+(-8)^{2}}$
D= $\sqrt{256+64}$
D= $\sqrt{320}$
D= $4 \sqrt{2}$
AD= $4 \sqrt{2}$

so we have
AD= $4 \sqrt{2}$
BC= $4 \sqrt{5}$
XY= $2 \sqrt{5}$

AD and BC are base1 and base 2
XY=height
so
(b1+b2) times 1/2 times height
( $4 \sqrt{2}+4 \sqrt{5}$ ) times 1/2 times $2 \sqrt{5}$ =
( $4 \sqrt{2}+4 \sqrt{5}$ ) times \sqrt{5} [/tex] =
$4 \sqrt{10}+4*5$ = $4 \sqrt{10}+20$ =80 $\sqrt{10}$ =252.982

X=(15,8)
Y=(13,4)
BC= $4 \sqrt{5}$
XY= $2 \sqrt{5}$
Area=80 $\sqrt{10}$ square unit or 252.982 square units

7 0

3 years ago

A caterer charger $120 to carter a party for 15 people and $200 for 25 people

Luba_88 [7]

Answer:

y = 8x

Step-by-step explanation:

When the number of people increased by 10, the caterer charged an additional $80. Therefore, we estimate that the cost per person is $8. In order to verify:

$8/person * 15 people = $120. True. $8/person * 25 people = $200. True.

Therefore, if we let x represent the number of people being cater for and y represent the cost, the equation to model the situation is simply y = 8x.

hope it helps!

5 0

3 years ago

Simplify 6m2n3 – 3m3n2 + 8m2n3 + 12m3n2

NISA [10]

Hello! Hope I can assist you.

Let us simplify some terms first!

$6m\cdot \:2n\cdot \:3 \ \textgreater \ 36mn$
$3m\cdot \:3n\cdot \:2 \ \textgreater \ 2\cdot \:3^2mn$
$8m\cdot \:2n\cdot \:3 \ \textgreater \ 48mn$
$12m\cdot \:3n\cdot \:2 \ \textgreater \ 72mn$

$36mn-2\cdot \:3^2mn+48mn+72mn$

From here, group like terms
$36mn-2\cdot \:3^2mn+48mn+72mn$

$\mathrm{Add\:similar\:elements:}\:36mn+48mn+72mn=156mn$
$156mn-2\cdot \:3^2mn$

$2\cdot \:3^2mn \ \textgreater \ 2\cdot \:9mn \ \textgreater \ 18mn$

$156mn-18mn$

$\mathrm{Add\:similar\:elements:}\:156mn-18mn=138mn$

Hope this helps!

6 0

3 years ago

How much interest will be earned in 4 years from $2,450 placed in a savings account at 6.5% simple interest? (Remember the I=PRT

Nikolay [14]

Answer:

6100.80

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers