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Bumek [7]
3 years ago
10

The entrance hall in Black's family house has a perimeter of 71 2/3 ft.IF it is 9 2/5 ft wide, how long is it?

Mathematics
1 answer:
serious [3.7K]3 years ago
3 0

Answer: 26 13/30 feet

Step-by-step explanation:

The hall is in the shape of a rectangle. The perimeter of a rectangle is:

= 2(length + width)

= 2l + 2w

Since perimeter = 71 2/3 ft and Width = 9 2/5 ft wide, the length will be calculated thus:

Perimeter = 2l + 2w

71⅔ = 2l + 2(9 2/5)

71 2/3 = 2l + (2 × 47/5)

71 2/3 = 2l + 94/5

71 2/3 = 2l + 18 4/5

Collect like terms

2l = 71 2/3 - 18 4/5

2l = 71 10/15 - 18 12/15

2l = 52 13/15

l = (52 13/15 ÷ 2)

l = 793/15 × 1/2

l = 793/30

l = 26 13/30

Therefore, the length is 26 13/30ft

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