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2 years ago

The ordered pairs (2, -21) and (5, -45) are solutions to which of the following equations?

Mathematics

1 answer:

Nadusha1986 [10]2 years ago

7 0

Answer:

A. y = -8x -5

Step-by-step explanation:

You will notice that when x increases from 2 to 5, y decreases from -21 to a number that is more negative. Thus only the first two answer choices are possibilities, since the others have a positive coefficient for x.

Trying the first given point in the first answer choice, we see that it works:

-21 = -8·2 -5

so, that is the equation we're looking for.

y = -8x -5

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MAVERICK [17]

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3 years ago

The midpoint M and one endpoint of JK are given. Find the coordinates of the other endpoint. J(7,2) and M(1,-2)

djverab [1.8K]

Step-by-step explanation:

Xj + Xk/2 = Xm

7 + Xk/2 = 1

to get rid of the bracket, multiply all two sides by the denominator.

2(7 + Xk/2) = 1(2)

7 + Xk = 2

Xk = 2 - 7

Xk = -5

Yj + Yk/2 = Ym

2 + Yk/2 = -2

to get rid of the bracket, multiply all two sides by the denominator.

2(2 + Yk/2) = -2(2)

2 + Yk = -4

Yk = -4 - 2

Yk = -6

Therefore the coordinates of point K is (-5,-6)

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3 years ago

I need help with this one been struggling for literal hours <br><br><br> 9+10

sertanlavr [38]

Answer:

The answer is 19

Step-by-step explanation:

10 plus 9 is 19

4 0

2 years ago

Read 2 more answers

I will give brainliest to best answer<br>Factorise completely (3x^2-5y^2)

Artemon [7]

<h2><em>we can write (3x^2-5y^2) as (3x-5y)^2</em></h2><h2><em>( 3 x − 5 y ) 2 as ( 3 x− 5 y ) ( 3 x− 5 y )</em></h2><h2><em>3 x ( 3 x − 5 y ) − 5 y ( 3x −5 y )</em></h2><h2><em>3 x ( 3 x − 5 y ) − 5 y (3 x − 5 y )</em></h2><h2><em>3 x ( 3 x ) + 3 x ( − 5y ) − 5 y ( 3 x ) − 5 y( -5 y )</em></h2><h2><em>9 x 2 − 15 x y − 15y x + 25 y 2 </em></h2><h2><em> Subtract 15 y x from − 15 x y .</em></h2><h2><em>9 x 2 − 30 xy + 25 y 2</em></h2><h2><em> HOPE IT HELPS(◕‿◕✿) </em></h2><h2><em> SMILE!! </em></h2>

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3 years ago

Simplify the expression by factoring, showing the steps in your work.

alexdok [17]

Given:

$$\frac{12 x^{2}+31 x+7}{16 x^{2}+8 x+1}$