Let er be the unit radial vector and r=x2+y2+z2−−−−−−−−−−√. Calculate the integral of F=e−rer over: (a) The upper-hemisphere of
x2+y2+z2=25 , outward-pointing normal (b) The region on the sphere of radius r=5 centered at the origin that lies inside the first octant x,y,z≥0 (a) ∬SF⋅dS=
1 answer:
You might be interested in
<u>Answer:</u>
<u>given:</u>
- adjacent side: 10
- hypotenuse side: 20
<u>using cosine rule:</u>
If angle 1 and angle 2 are <u>complementary, </u>then they add up to 90 degrees. We are given that angle 2 equals 52 degrees.
So we subtract and get our answer:
38
That's NOT the final answer.
The next step is:
Angle 1 and angle 3 are vertical angles.
Vertical angles are congruent.
So if angle 1 is 38, then angle 3 is also 38.
Now, supplementary angles add up to 180 degrees.
So that's the answer:
180-38=142
142 is the supplement of angle 3.
Hope it helps! :)
Answered by
If the shapes are similar, the correspondent sides are in proportion:
Let's plug the values and solve for x:
Multiply both sides by x to get
The only feasible solution, though, is , because it wouldn't make sense to have negative lengths.