<img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B216%5C%5C%7D" id="TexFormula1" title="\sqrt[3]{216\\}" alt="\sqrt[3]{216\\}"

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Alenkasestr [34]

2 years ago

9

align="absmiddle" class="latex-formula">

1 answer:

aivan3 [116]2 years ago

7 0

Answer:

6

Step-by-step explanation:

$\sqrt[3]{216}$ = $\sqrt[3]{8}$ · $\sqrt[3]{27}$ = $\sqrt[3]{2}$ ³ · $\sqrt[3]{3}$ ³ = 2 x 3 = 6

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The building below is shown to scale; for every 1 inch of drawing, it is 5 feet in actual distance. The exterior surface area of

VashaNatasha [74]

Answer:

50,000 square inches

Step-by-step explanation:

1:5 ratio so 250,000/5=50,000

8 0

2 years ago

Help With IXL P.10 plz!!!<br> Write you snap/insta down below, if you know how to do this please!!

Misha Larkins [42]

Answer:

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Step-by-step explanation:

8 0

2 years ago

Match the identities to their values taking these conditions into consideration sinx=sqrt2 /2 cosy=-1/2 angle x is in the first

BaLLatris [955]

Answer:

$\cos(x+y)$ goes with $-\frac{\sqrt{6}+\sqrt{2}}{4}$

$\sin(x+y)$ goes with $\frac{\sqrt{6}-\sqrt{2}}{4}$

$\tan(x+y)$ goes with $\sqrt{3}-2$

Step-by-step explanation:

$\cos(x+y)$

$\cos(x)\cos(y)-\sin(x)\sin(y)$ by the addition identity for cosine.

We are given:

$\sin(x)=\frac{\sqrt{2}}{2}$ which if we look at the unit circle we should see

$\cos(x)=\frac{\sqrt{2}}{2}$ .

We are also given:

$\cos(y)=\frac{-1}{2}$ which if we look the unit circle we should see

$\sin(y)=\frac{\sqrt{3}}{2}$ .

Apply both of these given to:

$\cos(x+y)$

$\cos(x)\cos(y)-\sin(x)\sin(y)$ by the addition identity for cosine.

$\frac{\sqrt{2}}{2}\frac{-1}{2}-\frac{\sqrt{2}}{2}\frac{\sqrt{3}}{2}$

$\frac{-\sqrt{2}}{4}-\frac{\sqrt{6}}{4}$

$\frac{-\sqrt{2}-\sqrt{6}}{4}$

$-\frac{\sqrt{6}+\sqrt{2}}{4}$

Apply both of the givens to:

$\sin(x+y)$

$\sin(x)\cos(y)+\sin(y)\cos(x)$ by addition identity for sine.

$\frac{\sqrt{2}}{2}\frac{-1}{2}+\frac{\sqrt{3}}{2}\frac{\sqrt{2}}{2}$

$\frac{-\sqrt{2}+\sqrt{6}}{4}$

$\frac{\sqrt{6}-\sqrt{2}}{4}$

Now I'm going to apply what 2 things we got previously to:

$\tan(x+y)$

$\frac{\sin(x+y)}{\cos(x+y)}$ by quotient identity for tangent

$\frac{\sqrt{6}-\sqrt{2}}{-(\sqrt{6}+\sqrt{2})}$

$-\frac{\sqrt{6}-\sqrt{2}}{\sqrt{6}+\sqrt{2}}$

Multiply top and bottom by bottom's conjugate.

When you multiply conjugates you just have to multiply first and last.

That is if you have something like (a-b)(a+b) then this is equal to a^2-b^2.

$-\frac{\sqrt{6}-\sqrt{2}}{\sqrt{6}+\sqrt{2}} \cdot \frac{\sqrt{6}-\sqrt{2}}{\sqrt{6}-\sqrt{2}}$

$-\frac{6-\sqrt{2}\sqrt{6}-\sqrt{2}\sqrt{6}+2}{6-2}$

$-\frac{8-2\sqrt{12}}{4}$

There is a perfect square in 12, 4.

$-\frac{8-2\sqrt{4}\sqrt{3}}{4}$

$-\frac{8-2(2)\sqrt{3}}{4}$

$-\frac{8-4\sqrt{3}}{4}$

Divide top and bottom by 4 to reduce fraction:

$-\frac{2-\sqrt{3}}{1}$

$-(2-\sqrt{3})$

Distribute:

$\sqrt{3}-2$

6 0

2 years ago

9 t-shirts and a hat costs £93 4 t-shirts and a hat costs £43 how much does the hat and t-shirt cost

alexandr402 [8]

Answer:

T-shirt costs £10

Hat costs £3

Step-by-step explanation:

£93-£43=£50

9-4=5

£50/5=10

1 t-shirt=£10

£10x9=£90

£93-£90=£3

T-shirt = £10

Hat= £3

4 0

3 years ago

Read 2 more answers

What is the value of r for 19 and 20?

nata0808 [166]

Answer:

19.) r = -4 20.) r = 1

Step-by-step explanation:

19.) Because we know the slope and have some points, we can use point-slope form to find the equation.

Point-slope form is:

y - y1 = m(x - x1)

Substitute the numbers into the equation:

y - 3 = 7/6(x - 1)

y - 3 = 7/6x -7/6

y = 7/6x + 11/6

Now that we know the equation, we can put in the x value to find the y (In this case, y = r):

r = 7/6(-5) + 11/6

r = -35/6 + 11/6

r = -4

20.) Because the slope is undefined, that means on the graph, the line will appear straight and vertical. This means the equation will be something like x = a number.

We have the point (1,4). Since we know that the x value will never change, we know that r will have to equal 1 as well.

r = 1

4 0

3 years ago