<img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B216%5C%5C%7D" id="TexFormula1" title="\sqrt[3]{216\\}" alt="\sqrt[3]{216\\}"

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Alenkasestr [34]

3 years ago

align="absmiddle" class="latex-formula">

Mathematics

1 answer:

aivan3 [116]3 years ago

7 0

Answer:

Step-by-step explanation:

$\sqrt[3]{216}$ = $\sqrt[3]{8}$ · $\sqrt[3]{27}$ = $\sqrt[3]{2}$ ³ · $\sqrt[3]{3}$ ³ = 2 x 3 = 6

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Consider the following hypothesis test. H0: μ ≥ 55 Ha: μ < 55 A sample of 36 is used. Identify the p-value and state your con

Ket [755]

Answer:

Step-by-step explanation:

Given that:

$H_o: \mu \ge 55 \ \\ \\ H_1 : \mu < 55$

(a) For x = 54 and s = 5.3

The test statistics can be computed as:

$Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }$

$Z = \dfrac{54-55}{\dfrac{5.3}{\sqrt{36}} }$

$Z = \dfrac{-1}{\dfrac{5.3}{6} }$

Z = -1.132

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(-1.132,35,1) = 0.1326

Decision: p-value is greater than significance level; do not reject $\mathbf{H_o}$

$Conclusion: \ There \ is \ insufficient \ evidence \ to \ conclude \ that \$ $\mu < 55$

For x = 53 and s = 4.6

The test statistics can be computed as:

$Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }$

$Z = \dfrac{53-55}{\dfrac{4.6}{\sqrt{36}} }$

$Z = \dfrac{-2}{\dfrac{4.6}{6} }$

Z = -2.6087

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(-2.6087,35,1) =0.0066

Decision: p-value is < significance level; we reject the null hypothesis.

$Conclusion: \ There \ is \ sufficient \ evidence \ to \ conclude \ that$ $\mu < 55$

For x = 56 and s = 5.0

The test statistics can be computed as:

$Z = \dfrac{\overline x - \mu}{\dfrac{s}{\sqrt{n}} }$

$Z = \dfrac{56-55}{\dfrac{5.0}{\sqrt{36}} }$

Z = 1.2

degree of freedom = n - 1

= 36 - 1

= 35

Using the Excel Formula:

P-Value = T.DIST(1.2,35,1) = 0.88009

Decision: p-value is greater than significance level; do not reject $\mathbf{H_o}$

$Conclusion: \ There \ is \ insufficient \ evidence \ to \ conclude \ that \$ $\mu < 55$

6 0

3 years ago

A patient with end-stage kidney disease has nine family members who are potential kidney donors. How many possible orders are th

eduard

Answer: 504

Step-by-step explanation:

When we select r things from n things in a order , we use permutations.

Formula for permutation: $^nP_r=\dfrac{n!}{(n-r)!}$

Given : The number of family members who are potential kidney donors. = 9

Number of people needed to be selected for best match, a second-best match, and a third-best match ( in an order)=3

Then, the number of possible orders are = $^9P_3=\dfrac{9!}{(9-3)!}$

$=\dfrac{9\times8\times7\times6!}{6!}=504$

Hence, the number of possible orders 504.

4 0

3 years ago

In one day, the stock price for Warbucks Coffee rose from $50 to $57 per share. By what percent did this stock price rise?

egoroff_w [7]

Answer:

14%

Step-by-step explanation:

1. The formula to find percent change is $\frac{(V_2-V_1)}{|V_1|} * 100$ . Now, all we have to do is plug in the values to their corresponding variable.

2. (Solving)

$\frac{(57-50)}{|50|} * 100$
$\frac{7}{50} *100$

$0.14 * 100$
14%

7 0

3 years ago

Find the area of each figure, round to the nearest tenth if necessary.USE 3.14 for pi

Nina [5.8K]

Answer:

11 is 405, 12 is 107.5, 13 im not sure of

Step-by-step explanation:

First on 11 you can just do 21*21 (the big square) and subtract that by 36 (which is 6*6, the small square), you'll get 107.5.

Then on 12, it is made up of a large rectangle, a small triangle, and a flatter triangle. The top triangle's formula is 1/2(7*3) which = 10.5. The big rectangle is 13*7 = 91. The last triangle is 1/2(4*3) which = 6. It is 3 because 13-10. Add all those up and you should get 107.5.

And I just want to know on number 13 if that 11 is the radius or diameter. I can't seem to tell.

7 0

3 years ago

Read 2 more answers

Help huryyyyyyyyyyyyy

zhuklara [117]

Answer: 4

Step-by-step explanation:

Because %s can be expressed as fractions over 100, because 90 is 70% of x, 70% is 70% of 100. Thus, 90/x = 70/100.

<em>Hope it helps <3</em>

8 0

3 years ago

Read 2 more answers