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ehidna [41]
3 years ago
10

Solve for the variable x- 8= – 8

Mathematics
2 answers:
kiruha [24]3 years ago
4 0

Answer:x=0

Step-by-step explanation:

x-8=-8

x=-8+8

x=0

Lyrx [107]3 years ago
3 0

Answer:

x=0

Step-by-step explanation:

X -8 = -8

Add 8 to both sides to get x alone

X = 8 - 8

X = 0

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Solve for <br> 3x + 12= -12
oee [108]

Answer:

x = -8

Step-by-step explanation:

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

First, subtract 12 from both sides:

3x + 12 (-12) = -12 (-12)

3x = -12 - 12

3x = -24

Next, divide 3 from both sides:

(3x)/3 = (-24)/3

x = -24/3

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x = -8 is your answer.

~

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4 years ago
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you get $2,000 loan at 9% interest rate and pays it back in 6 months. how much intereast will you pay on the loan
notka56 [123]

Answer:

$90

Step-by-step explanation:

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then, solving our equation

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3 years ago
CAN ANYBODY HELP ME OUT
bija089 [108]

Answer:

Correct option is

b. If two sides and one included angle are equal in triangles PQS and PRS, then their corresponding sides are also equal.

Step-by-step explanation:

Here, we are given the line RQ, which is divided in two equal parts by a line PS which is perpendicular to RQ.

The foot S of PS is on the line RQ.

First of all, let us do a construction here.

Join the point R with P and P with Q.

Please refer to the attached image.

Now, let us consider the triangles  PQS and PRS:

  • Side QS = RS (as given)
  • \angle PSR = \angle PSQ = 90^\circ
  • Side PS = PS (Common side in both the triangles)

Now, Two sides and the angle included between the two triangles are equal.

So by SAS congruence we can say that \triangle PRS \cong \triangle PQS

Therefore, the corresponding sides will also be equal.

RP = QP

RP is the distance between R and P.

QP is the distance between Q and P.

Hence, to prove that P is equidistant from R and Q, we have proved that:

b. If two sides and one included angle are equal in triangles PQS and PRS, then their corresponding sides are also equal.

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