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Arlecino [84]
2 years ago
15

2 1/2 divided by 5 equals?? Options: 25/2 12 1/2 1/2 5/10

Mathematics
1 answer:
aivan3 [116]2 years ago
3 0

Answer:

1/2

Step-by-step explanation:

calculator, i guess I won't improve your skills :(

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Find the slope of the line that passes through (4, 6) and (2, 3).
Verizon [17]
The slope is 3/2

To find the slope, you have to use the slope formula

y2-y1/x2-x1

6-3/4-2

3/2

So the slope is 3/2
3 0
3 years ago
Urgent help!
evablogger [386]

Answer:

charge for d days=d×75$

charge for k kilometers=k×65cents

total cost=75d$+k×0.65$

c=(75d+0.65k)$

6 0
3 years ago
Select the correct answer.
Afina-wow [57]

Answer:

d)\ \frac{81}{m^{7}}

Step-by-step explanation:

(3m^-4)^3(3m^5)

First, simplify (3m^{-4})^3:

(3m^{-4})^3\\\\3^3*m^{-4*3}\\\\27m^{-12}

27m^{-12}*3m^5\\\\27*3 *m^{-12+5}\\\\81m^{-7}\\\\81*\frac{1}{m^{7}} \\\\\frac{81}{m^{7}}

Hope this helps!

5 0
2 years ago
What is the period of the graph y=1/2sin (pix)+3?<br><br> A- 3<br> B- 1/2<br> C-pi <br> D-2
dimaraw [331]

The period is 2.

Normally the period of sin(x) is 2pi, but the pi inside the sin(pix) is a horizontal compression by a factor of 1/pi.  So 2pi·1/pi = 2

The "1/2" and "+3" do not impact the period.  Those just impact the amplitude (vertical aspect) of the graph.

3 0
3 years ago
A certain region currently has wind farms capable of generating a total of 2500 megawatts ​(2.5 ​gigawatts) of power. Complete p
marishachu [46]

Answer:

<u>The correct answer is A. 7,665'000,000 kilowatt-hours per year and B. 766,500 households.</u>

Step-by-step explanation:

1. Let's review the information provided to us for solving the questions:

Power capacity of the wind farms = 2,500 Megawatts or 2.5 Gigawatts

2. Let's resolve the questions a and b:

Part A

Assuming wind farms typically generate 35​% of their​ capacity, how much​ energy, in​ kilowatt-hours, can the​ region's wind farms generate in one​ year?

2,500 * 0.35 = 875 Megawatts

875 Megawatts = 875 * 1,000 Kilowatts = 875,000 Kilowatts

Now we calculate the amount of Kilowatts per hour, per day and per year:

875.000 Kw generated by the farms means that are capable of produce 875,000 kw per hour of energy

875,000 * 24 = 21'000,000 kilowatt-hours per day

<u>21'000,000 * 365 = 7,665'000,000 kilowatt-hours per year</u>

Part B

Given that the average household in the region uses about​ 10,000 kilowatt-hours of energy each​ year, how many households can be powered by these wind​ farms?

For calculating the amount of households we divide the total amount of energy the wind farms can generate (7,665'000,000 kilowatt-hours) and we divide it by the average household consumption (10,000 kilowatt-hours)

<u>Amount of households =  7,665'000,000/10,000 = 766,500</u>

4 0
3 years ago
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